Answer:
The values of p in the equation are 0 and 6
Step-by-step explanation:
First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p
2
−7p−4=(2p+1)(p−4)
So then the equation looks like:
\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}
2p+1
p
−
(2p+1)(p−4)
2p
2
+5
=−
p−4
5
To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:
\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}
(2p+1)(p−4)
p
2
−4p
−
(2p+1)(p−4)
2p
2
+5
=−
(p−4)(2p+1)
10p+5
Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.
(p^2-4p)-(2p^2+5)=-(10p+5)(p
2
−4p)−(2p
2
+5)=−(10p+5)
Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p
2
−4p)−(2p
2
+5) first:
(p^2-4p)-(2p^2+5)=-p^2-4p-5(p
2
−4p)−(2p
2
+5)=−p
2
−4p−5
-p^2-4p-5=-10p+5−p
2
−4p−5=−10p+5
Combine like terms:
-p^2-4p+0=-10p−p
2
−4p+0=−10p
-p^2+6p=0−p
2
+6p=0
Factor:
p=0, p=6p
Answer:
A scale to plot data
It is hard to tell the difference between the choices. If they are the following:
- a starting point with equal intervals that follow
- a stopping point for the data that can fit on the graph
- a way to locate data
- a scale to plot data
A is the answer. It has no repeating x points buy it repeats on the y coordinate, which is okay. The answer is A just to say it again.
I was thinking that the answer could be
2.810; log3 21.903
OR
<span> 2.810; log3 55.2 </span>
So,<span> log5 of 92 is between 2.5 and 3 Correct answer is A</span>
Answer:
Ok
A. 33x - 14
B. 18x - 10
C. a - 20
D. 40a + 5
E. 5n - 24
F. - 16n + 37
G. -7x + 12
H. 15x + 28
I. - 7a +24
J. 13a - 27
K. -48n - 16
J. - 12n + 35
Well hope all this helps :)
Step-by-step explanation:
