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Fiesta28 [93]
3 years ago
8

Please help This is Solve percent problems, part 1 on I-ready

Mathematics
1 answer:
Olenka [21]3 years ago
5 0

Answer:

70/100 (58)

0.70 (58)

Step-by-step explanation:

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What is the equation of the graphed line written in standard form?
Dmitry_Shevchenko [17]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Solve for x.<br><br> x3=125<br><br> Enter your answer in the box.<br><br> x =
olchik [2.2K]

Answer:

x = 5

Step-by-step explanation:

 =(-5-√-75)/2=(-5-5i√ 3 )/2= -2.5000-4.3301i

x =(-5+√-75)/2=(-5+5i√ 3 )/2= -2.5000+4.3301i

x = 5

source tiger-algebra.com

4 0
3 years ago
Read 2 more answers
What is the area, in square units, of the trapezoid?
Misha Larkins [42]

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Step-by-step explanation:

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6 0
3 years ago
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
Please help ASAP. Thanks so much.
MAVERICK [17]

Answer:

B. 3

Step-by-step explanation:

To find the value of c, substitute the x and y values of the given point into x and y of the equation, then isolate c. Since that given point is (2,5), substitute 2 for x and 5 for y:

(5) = -2(2)^2+8(2)-c\\5 = -2(4)+16-c\\5 = -8 + 16 - c \\5 = 8 -c\\-3 = -c\\c = 3

Thus, c = 3.

5 0
3 years ago
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