Given
Endpoints of the diameter (5,2) and (-7,4)
Step One
Find the center
Center = (x2 + x1)/2 , (y2 + y1)/2
x2 = -7; x1 = 5; y2 = 4; y1 = 2
Center = (-7 + 5)/2 ; (4 + 2)/2;
Center = (-1 , 3)
Step Two
Find the radius squared using the distance formula. Use (5,2) as the second point. The other point is the center.
Distance squared = (5 - - 1)^2 + (2 - 3)^2
Distance squared = ( 6)^2 + (-1 )^2
Distance squared = 37
Step Three
State the circle's formula
(x - - 1 )^2 + (y - 3)^2 = 37
(x + 1)^2 + (y - 3)^2 = 37
Let's start off with some key terms.
The number has 3 digits.
Even numbers end with 0, 2, 4, 6, or 8. (Obviously)
The hundreds digit and ones digit are the same.
First number in a 3 digit number is the
hundreds, and the last number is the
ones.
So, both of those two digits are the same and has to equal 8.
Well,
The hundreds place and the ones place are 4.
The tens digit is the middle number in a 3-digit number.
It is two numbers less than the ones digit.
The number is 424.