Irrational numbers are numbers that can not be written as a simple fraction. An example of one would be $\pi$ . Pi is about 3.14, but it goes on forever. You can not write pi as a simple fraction.

6 0

3 years ago

6. a) Calculate the areas of the three squares. b) Is the triangle a right triangle? Explain. 3 cm 4 cm 2 cm

viktelen [127]

Answer

The total area of the squares = 29 square cm

The triangle is not a right-angled triangle

Step-by-step explanation:

We are given three squares

The first square has a length of 4cm

The second square has a length of 3cm

The third square has a length of 2cm

Part A

Total area = Area of square 1 + Area of square 2 + Area of square 3

Area of a square = l^2

Where l is the length of the square

Area of a square 1 = 4^2

Area of a square = 16 square cm

Area of square 2 = 3^2

Area of square 2 = 9 square cm

Area of square 3 = 2^2

Area of square 3 = 4 square cm

Total area of the square = 16 + 9 + 4

The total area of the square = 29 square cm

Hence, the total square of the figure is 29 square cm

Part B

$\begin{gathered} \text{ To proof if the triangle is a right angled triangle} \\ \text{ We n}eed\text{ to appy Pythagora's theor}em \\ \text{Hypotenus}^2=perpendicular^2+base^2 \\ \text{Hypotenus = 4}cm \\ \text{Perpendicular =3cm} \\ \text{Base = 2cm} \\ 4^2=3^2+2^2 \\ 16\text{ = 9 + 4} \\ 16\text{ }\ne\text{ 13} \\ \text{ Since the hypotenus is not equal to the summation of the perpendicular and base} \\ \text{Hence, the triangle is a not right angled triangle} \end{gathered}$

6 0

1 year ago

Please help me answer this question ASAP! If you give me a stupid answer I will report your account

VladimirAG [237]

Answer:

Step-by-step explanation:

It is linear.

We can see the right side are multiples of 3. So the equation so the table is:

c = 3h

When h = 5 c = 15

c = 3h

c = 3*5

c = 15

When h = 12 c = 36

c = 3h

c = 3*12

c = 36

The constant rate of change between cost and time is 3.

Another way to solve is check for rate of change using 2 points on the chart.

Let's choose h = 5 c = 15 and h = 12 c = 36

The normal equation for rate of change is:

m = $\frac{y_{2} -y_{1}}{x_{2}-x_{1}}$ in this case we have h and c so:

$\frac{c_{2} -c_{1}}{h_{2}-h_{1}}$

h₁ = 5 h₂ = 12

c₁ = 15 c₂ = 36

So:

$\frac{c_{2} -c_{1}}{h_{2}-h_{1}} = \frac{36 -15}{12-5} = \frac{21}{7} = \frac{3}{1} =3$

Now that we know it's 3 we use slope intercept form to find the equation.

y = mx + b ( m = 3) and we plug in a point to find b.

y = 3x + b h = 5 (x) c = 15 (y)

15 = 3(5) + b Solve for b.

15 = 15 + b Subtract 15 from each side.

15 - 15 = 15 - 15 + b

0 = b b is 0 showing our equation was correct.

y = 3x or c = 3h

6 0

2 years ago