A) y = 2x – 7 and f(x) = 7 – 2xIncorrect. These equations look similar but are not the same. The first has a slope of 2 and a y-intercept of −7. The second function has a slope of −2 and a y-intercept of 7. It slopes in the opposite direction. They do not produce the same graph, so they are not the same function. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5. B) 3x = y – 2 and f(x) = 3x – 2Incorrect. These equations represent two different functions. If you rewrite the first equation in terms of y, you’ll find the equation of the function is y = 3x + 2. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5. C) f(x) = 3x2 + 5 and y = 3x2 + 5Correct. The expressions that follow f(x) = and y = are the same, so these are two different ways to write the same function: f(x) = 3x2 + 5 and y = 3x2 + 5. D) None of the aboveIncorrect. Look at the expressions that follow f(x) = and y =. If the expressions are the same, then the equations represent the same exact function. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5.
Answer:
103.9 lb.
Step-by-step explanation:
T cos 30°+T cos 30°=180
2T cos 30°=180
T=103.9 lb.
Answer:
70
Step-by-step explanation:
Answer and explanation:
1. 2 × 3/10 = 6/10 = 3/5
2. 8 × 4/8 = 32/8 = 4
3. 9 × 3/9 = 27/9 = 3
4. 12 × 2/11 = 24/11 = 2 2/11
5. 3 × 5/7 = 15/7 = 2 1/7
6. 2 × 3/5 = 6/5 = 1 1/5
7. 11 × 4/8 = 44/8 = 5 4/8 = 5 1/2
8. 10 × 1/4 = 10/4 = 2 2/4 = 2 1/2
9. 5 × 1/4 = 5/4 = 1 1/4
10. 11 × 2/7 = 22/7 = 3 1/7
Hope this helps!
Answer:
c
Step-by-step explanation:
come on ! you can literally see that in the chart.
how many parts of the gray 3/8 are covered by the gray 1/4 ?
2 parts = 2/8 are clearly covered by 1/4.
2/8 is what part of 3/8 ?
it is the same question as "2 is what part of 3" ?
is 2 a quarter (1/4) of 3 ? no, 1/4×3 = 3/4 and not 2.
is 2 one third (1/3) of 3 ? no, 1/3 of 3 = 1/3×3 = 1 and not 2.
is 2 two thirds (2/3) of 3 ? ah, 2/3 × 3 = 2. that is correct !
is 2 three quarters (3/4) of 3 ? no, 3/4×3 = 9/4 and not 2.
once you have the same denominator, you can easily compare the numerators and ignore the denominators for such problems.
