Part of the proceeds from a garage sale was $470 worth of $10 and $20 bills. If there were 14 more $10 bills than $20 bills, fin

Question

3 years ago

8

d the number of each denomination There were $10 bills and $ 20 bills

1 answer:

Brums [2.3K] · Answer 1 · 2022-07-05T18:05:28+03:00

There are 25 $10 bills and 11 $20 bills.

Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

x be the number of $10 bills

y be the number of $20 bills.

According to given situation;

10x+20y=470 Eqn 1

x = y+14 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$10(y+14)+20y=470\\10y+140+20y=470\\30y=470-140\\30y=330$

Dividing both sides by 30

$\frac{30y}{30}=\frac{330}{30}\\y=11$

Putting y=11 in Eqn 2

$x=11+14\\x=25$

There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

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