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Natasha_Volkova [10]
3 years ago
11

Find the equation of the line using the point-slope formula. Write the final equation using the slope-intercept form. perpendicu

lar to 8y = x − 4 and passes through the point (−2, 1)
Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Answer:

point-slope form;

(y - 1) = -8(x+2)

slope-intercept form;

y = -8x - 15

Step-by-step explanation:

The first step is to determine the slope of the given line;

8y = x − 4

y = 1/8(x) - 1/2..... After dividing both sides by 8

The slope of the line is thus 1/8, the coefficient of x when the equation is written in slope-intercept form.

The required line is perpendicular to this given line which implies that the product of the slopes will be equal to -1. Let the slope of the required line be m;

m * 1/8 = -1

m = -8

The slope of the required line is thus -8. Using the given point,  (−2, 1), the equation of this line in point-slope form becomes;

(y - 1) = -8(x - -2)

(y - 1) = -8(x+2)

We make y the subject of the formula;

y = -8x - 16 + 1

y = -8x - 15

This is the slope-intercept form of the equation of the line.

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Tentukan persamaan garis yang di wakili ruas garis AB,BC,CD dan AD! <br>tolong kak
Ann [662]

Answers:

1. AB: y = - 2x - 6

2. BC: y = x - 3

3. CD: x = 3

4. AD: y = (3/7) x +26/7


Solution:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)


1. AB

A=(-4,2)=(xa, ya)→xa=-4, ya=2

B=(-1,-4)=(xb, yb)→xb=-1, yb=-4

mab=(yb-ya)/(xb-xa)

mab=(-4-2)/(-1-(-4))

mab=(-6)/(-1+4)

mab=(-6)/(3)

mab=-2

y-ya=mab (x-xa)

y-2=-2(x-(-4))

y-2=-2(x+4)

y-2=-2x-8

y-2+2=-2x-8+2

y=-2x-6


2. BC

B=(-1,-4)=(xb, yb)→xb=-1, yb=-4

C=(3,0)=(xc, yc)→xc=3, yc=0

mbc=(yc-yb)/(xc-xb)

mbc=(0-(-4))/(3-(-1))

mbc=(0+4)/(3+1)

mbc=(4)/(4)

mbc=1

y-yc=mbc (x-xc)

y-0=1 (x-3)

y=x-3


3. CD

C=(3,0)=(xc, yc)→xc=3, yc=0

D=(3,5)=(xd, yd)→xd=3, yd=5

mcd=(yd-yc)/(xd-xc)

mcd=(-4-0)/(3-3)

mcd=(-4)/(0)

mcd= Infinite (Vertical line)

Equation vertical line: x=xc=xd

x=3


4. AD

A=(-4,2)=(xa, ya)→xa=-4, ya=2

D=(3,5)=(xd, yd)→xd=3, yd=5

mad=(yd-ya)/(xd-xa)

mad=(5-2)/(3-(-4))

mad=(3)/(3+4)

mad=3/7

y-ya=mad (x-xa)

y-2=(3/7)(x-(-4))

y-2=(3/7)(x+4)

y-2=(3/7)x+12/7

y-2+2=(3/7)x+12/7+2

y=(3/7)x+(12+7(2))/7

y=(3/7)x+(12+14)/7

y=(3/7)x+26/7


8 0
3 years ago
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