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Natasha_Volkova [10]
4 years ago
11

Find the equation of the line using the point-slope formula. Write the final equation using the slope-intercept form. perpendicu

lar to 8y = x − 4 and passes through the point (−2, 1)
Mathematics
1 answer:
Tanya [424]4 years ago
3 0

Answer:

point-slope form;

(y - 1) = -8(x+2)

slope-intercept form;

y = -8x - 15

Step-by-step explanation:

The first step is to determine the slope of the given line;

8y = x − 4

y = 1/8(x) - 1/2..... After dividing both sides by 8

The slope of the line is thus 1/8, the coefficient of x when the equation is written in slope-intercept form.

The required line is perpendicular to this given line which implies that the product of the slopes will be equal to -1. Let the slope of the required line be m;

m * 1/8 = -1

m = -8

The slope of the required line is thus -8. Using the given point,  (−2, 1), the equation of this line in point-slope form becomes;

(y - 1) = -8(x - -2)

(y - 1) = -8(x+2)

We make y the subject of the formula;

y = -8x - 16 + 1

y = -8x - 15

This is the slope-intercept form of the equation of the line.

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Help! asap!! 10 points! will give brainliest!!!
Mnenie [13.5K]

Using the Pythagorean Theorem, we have that the distance from home plate to second base is about 127 feet.

<h3>What is the Pythagorean Theorem?</h3>

The Pythagorean Theorem relates the length of the legs l_1 and l_2 of a right triangle with the length of the hypotenuse h, stating that the hypotenuse squared is the <u>sum of the legs squared</u> of the triangle, according to the following equation:

h^2 = l_1^2 + l_2^2

The distance between each consecutive base is of 90 feet, hence the distance from home plate to 2nd base is the hypotenuse of a <u>right triangle in which the legs are of 90 feet</u>, being the distances from home plate to 1st base and 1st base to 2nd base.

Then:

h² = 90² + 90²

h = sqrt(90² + 90²)

h = 127 feet.

The distance from home plate to second base is about 127 feet.

More can be learned about the Pythagorean Theorem at brainly.com/question/654982

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7 0
1 year ago
A student comes to lecture at a time that is uniformly distributed between 5:09 and 5:14. Independently of the student, the prof
scZoUnD [109]

Answer:

1/2

Step-by-step explanation:

The lecture has already begun when the student arrives means one of these scenarios happen:  

1) the class started at 5:10 and the student arrives at 5:11 or 5:12 or 5:13 or 5:14

2) the class started at 5:11 and the student arrives at 5:12 or 5:13 or 5:14

3) the class started at 5:12 and the student arrives at 5:13 or 5:14

Given student time of arrival is uniformly distributed, then the probability he/she arrives at 5:09 or 5:10 or 5:11 or 5:12 or 5:13 or 5:14 is 1/6.

So,  the probability that the student arrives between 5:11 and 5:14 is 1/6 + 1/6 + 1/6 + 1/6 = 2/3.

The probability that the student arrives between 5:12 and 5:14 is 1/6 + 1/6 + 1/6 = 1/2.

The probability that the student arrives at 5:13 or 5:14  is 1/6 + 1/6 = 1/3.

Given class starting time is uniformly distributed, then the probability it starts at 5:10 or  5:11 or 5:12 is 1/3.

Given the two events are independent, the probability of the first scenario is: (1/3)*(2/3) = 2/9

For the second scenario:  (1/3)*(1/2) = 1/6

For the third scenario:  (1/3)*(1/3) = 1/9

Because all of these scenarios are mutually exclusive the total probability of one of them happen is: 2/9 + 1/6 + 1/9 = 1/2

3 0
3 years ago
Expand the following:<br> c) 4(2x +1)
murzikaleks [220]

Answer:

= 4(2x +1)

= 4× 2x + 4×1

= 8x +4

6 0
3 years ago
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                                                           Part A)

Given

  • Slope m = 6
  • Point (7, 2)

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

  • m = 6
  • (x₁, y₁) = (7, 2)

substituting the values m = 6 and the point (x₁, y₁) = (7, 2) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - 2 = 6(x-7)

Therefore, the equation in​ point-slope form for the line having the slope m = 6 and containing the points (7,2) will be:

y - 2 = 6(x-7)

                                                        Part B)

Given

  • Slope m = -3
  • Point (3, 8)

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

  • m = -3
  • (x₁, y₁) = (3, 8)

substituting the values m = -3 and the point (x₁, y₁) = (3, 8) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - 8 = -3(x-3)

Therefore, the equation in​ point-slope form for the line having the slope m = -3 and containing the points (3, 8) will be:

y - 8 = -3(x-3)        

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Answer:

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Step-by-step explanation:

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