Answer:
point-slope form;
(y - 1) = -8(x+2)
slope-intercept form;
y = -8x - 15
Step-by-step explanation:
The first step is to determine the slope of the given line;
8y = x − 4
y = 1/8(x) - 1/2..... After dividing both sides by 8
The slope of the line is thus 1/8, the coefficient of x when the equation is written in slope-intercept form.
The required line is perpendicular to this given line which implies that the product of the slopes will be equal to -1. Let the slope of the required line be m;
m * 1/8 = -1
m = -8
The slope of the required line is thus -8. Using the given point, (−2, 1), the equation of this line in point-slope form becomes;
(y - 1) = -8(x - -2)
(y - 1) = -8(x+2)
We make y the subject of the formula;
y = -8x - 16 + 1
y = -8x - 15
This is the slope-intercept form of the equation of the line.
