Answer:
Step-by-step explanation:
A 2nd order polynomial such as this one will have 2 roots; a 3rd order polynomial 3 roots, and so on.
The quadratic formula is one of the faster ways (in this situation, at least) in which to find the roots. From 2x^2 + 4x + 7 we get a = 2, b = 4 and c = 7.
Then the discriminant is b^2 - 4ac, or, here, 4^2 - 4(2)(7), or -40. Because the discriminant is negative, we know that the roots will be complex and unequal.
Using the quadratic formula:
-4 ±√[-40] -4 ± 2i√10
x = ------------------ = ------------------
4 4
-2 ± i√10
Thus, the roots are x = ------------------
2
Answer:
i dont know lol but anyways
Step-by-step explanation:
Answer:
-5.5
Step-by-step explanation:
Answer: √y
<u>Step-by-step explanation:</u>
![\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7By%5E3%7D%3Dy%5E%7B%5Cfrac%7B3%7D%7B6%7D%7D%3Dy%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cboxed%7B%5Csqrt%20y%7D)
