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3 years ago

100 points, Hi, I’m not sure what to do here,the data doesn’t seem to be quadratic .?

Mathematics

2 answers:

Triss [41]3 years ago

7 0

Answer:

y=24.093915 + 0.02876392 x^2

Step-by-step explanation:

Minimize sum of squared deviations

I did it by hand on Android spreadsheet

x y f(x) (y-f(x))^2

0 25 24.093915 0.8209900272

5 23 23.374817 0.1404877835

10 20 21.217523 1.482362256

15 15 17.622033 6.875057053

20 13 12.588347 0.1694581924

25 9 6.116465 8.314774096

sum of squared devìation from the line 17.80312941

Ganezh [65]3 years ago

5 0

Answer:

Use quadratic regression on your calculator.

See my graph below.

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Answer:

Step-by-step explanation:

(X+4) (x^2 +1)

5 0

3 years ago

PLEASE HELP QUICK I WILL MARK BRAINLIEST!

Katena32 [7]

The answer to your question is the last option because the total of the whole table is 1.0. And, mathematically speaking, y cannot possibly be 1.0 if the tables values all add up to 1.0

6 0

3 years ago

Can someone help me on this ?

katrin2010 [14]

Answer:

1.) A=Bh-Bh=First Image

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Step-by-step explanation:

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6 0

3 years ago

A home-based sign company uses this function to model its monthly profit, where x is the price of each sign it sells.

kifflom [539]

Answer:

$p(20) = 4460$

Step-by-step explanation:

Given

$p(x) = -10x^2 + 498x - 1500$

Required

Evaluate p(x) when x = 20

To do this, we simply substitute 20 for x

$p(x) = -10x^2 + 498x - 1500$

$p(20) = -10 * 20^2 + 498 * 20 - 1500$

$p(20) = -10 * 400 + 9960 - 1500$

$p(20) = -4000 + 9960 - 1500$

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Option C answers the question

7 0

3 years ago

Section 5.2 Problem 6: Find the general solution <img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2

mihalych1998 [28]

Answer:

$y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Step-by-step explanation:

Given Second-Order Homogenous Differential Equation

$y''+6y'+10y=0$

Use Auxiliary Equation

$m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i$

General Solution

$y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Note that the DE has two distinct complex solutions $p\pm qi$ where $A$ and $B$ are arbitrary constants.

4 0

2 years ago