The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Step-by-step explanation:
from what I can see there are 2 options to make the 2 triangles congruent :
either the opposite sides must be equal or the neighboring sides must be equal.
so, either
5x = 3x + 10
and
5x - 2 = 4x + 3
or
5x = 4x + 3
and
5x - 2 = 3x + 10
for the first
5x = 3x + 10
2x = 10
x = 5
control
5x - 2 = 4w + 3
5×5 - 2 = 4×5 + 3
23 = 23
correct.
for the second
5x = 4x + 3
x = 3
control
5×3 - 2 = 3×3 + 10
15 - 2 = 9 + 10
13 = 19
no, not a valid solution.
so, x = 5
P(x) = 4x + 1550 <== ur function
selling only 50 copies...
P(50) = 4(50) + 1550
P(50) = 200 + 1550
P(50) = 1750....so the printing cost for 50 copies is 1750
1750 = 50x....x = cost of each book
1750/50 = x
35 = x.......u would have to sell each book for $ 35 <===
Answer:
74.82
Step-by-step explanation:
48+38=86 86 X 0.87= 74.82
