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2 years ago

Linda just bought 7 bags of 14 cookies each. She already had 8 cookies in a jar. How many cookies does Linda have now?

Mathematics

2 answers:

Troyanec [42]2 years ago

5 0

Answer:

106

Step-by-step explanation:

Tems11 [23]2 years ago

4 0

Answer:

106

Step-by-step explanation:

(14 x 7) + 8 = 106

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What would the answer be ? Thank You!!

Bogdan [553]

Answer:

2.33 = BC

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan B = AC / BC

tan 25 = AC / 5

Multiply each side by 5

5 tan 25 = BC

2.331538291 = BC

To the nearest hundredth

2.33 = BC

3 0

3 years ago

An atrium is being designed to house an exhibit of tropical birds. The atrium must enclose 250,000 cubic feet of space, and the

9966 [12]

The proposed design of the atrium (V < V') is possible since its volume is less than the maximum possible atrium.

<h3>Can this atrium be built in the rectangular plot of land?</h3>

The atrium with the maximum allowable radius (R), in feet, is represented in the image attached. The real atrium is possible if and only if the real radius (r) is less than the maximum allowable radius and therefore, the real volume (V), in cubic feet, must be less than than maximum possible volume (V'), in cubic feet.

First, we calculate the volume occupied by the maximum allowable radius:

V' = (8 · π / 3) · (45 ft)³

V' ≈ 763407.015 ft³

The proposed design of the atrium (V < V') is possible since its volume is less than the maximum possible atrium. $\blacksquare$

To learn more on volumes, we kindly invite to check this verified question: brainly.com/question/13338592

3 0

2 years ago

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$