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3 years ago

Find the value of each of these quantities. C(5,3) C(8,8) C(12,6)

1 answer:

7 0

$C^n_k= \frac{n!}{(n-k)!c!} 
\\
\\C^5_3= \frac{5!}{(5-3)!3!} = \frac{5!}{2!3!} = \frac{5\times4\times3}{3\times2\times1} =10
\\
\\C^8_8= \frac{8!}{(8-8)!8!} = \frac{8!}{0!8!} = \frac{8!}{1\times8!}=1
\\
\\C^{12}_6= \frac{12!}{(12-6)!6!} = \frac{12!}{6!6!} = \frac{12\times11\times10\times9\times8\times7}{6\times5\times4\times3\times2\times1} =\frac{11\times3\times4\times7}{1} =924$

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

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Step-by-step explanation:

Given that,

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By comparing with y′+p(t)y=g(t), we get

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Step-by-step explanation:

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