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maks197457 [2]
2 years ago
15

URGENT! So I need 55 turned into a fraction, with 3 being the denominator. Thanks

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
4 0
18 and 1/3


Just typing random letters
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$36\%$ of the beans in Pythagoras's soup are lentils, and $33\frac13\%$ of those lentils are green. If Pythagoras removes all th
bulgar [2K]

Question is not proper, Proper question is given below;

36% of the beans in Pythagoras's soup are lentils, and 33 1/3% of those lentils are green.

If Pythagoras removes all green lentils from his soup, then x% of the original beans remain. What is x?

Answer:

88% of the original beans remains (x) after removing green lentils.

Step-by-step explanation:

Given:

Let the Original beans be 'n'.

Now given:

36% of the beans in Pythagoras's soup are lentils.

So we can say that;

Amount of lentils = \frac{36}{100}n=0.36n

Also Given:

33 1/3% of those lentils are green

Amount of green lentils = 33\frac{1}{3}\%\ \ Or \ \ \frac{100}{3}\%

Amount of green lentils = \frac{100}{3}\times 0.36n\times\frac{1}{100}= 0.12n

Now we need find the percentage of original beans remain after removing green lentils.

Solution:

percentage of original beans remain  ⇒ x\%

To percentage of original beans remain after removing green lentils we will subtract Amount of green lentils from Original beans  and then multiplied by 100.

framing in equation form we get;

x\% = (n-0.12n)\times 100=88n \ \ \ Or \ \ \ 88\%

Hence 88% of the original beans remains (x) after removing green lentils.

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23 bby <3

Step-by-step explanation:

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