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dusya [7]
3 years ago
14

What fractions are equivalent to 18/12

Mathematics
2 answers:
Vlad [161]3 years ago
5 0
These are both simplified and not 9/6, 3/2, 6/4
Naya [18.7K]3 years ago
5 0
Well, 18/12 can be divisible by 6'3' and 2. So 3/2, 6/4, 9/6.
You might be interested in
Multiply the following complex numbers:<br>(7-3i)(8 + 4i)​
mel-nik [20]

Answer:

A

Step-by-step explanation:

Noting that i² = - 1

Given

(7 - 3i)(8 + 4i) ← expand factors using FOIL

= 56 + 28i - 24i - 12i²

= 56 + 4i - 12(- 1)

= 56 + 4i + 12

= 68 + 4i → A

3 0
3 years ago
∠A and ∠B are vertical angles. If m ∠A=(2x+26)∘ and ∠B=(3x−29)∘, then find the measure of ∠A.
Leya [2.2K]

The measure of angle (m ∠A) is 136°

<h3>Vertical angles theorem</h3>

From the question, we are to find the measure of angle A

From the given information, we have that

∠A and ∠B are vertical angles

Thus

∠A = ∠B

and

Also, from the given information,

m ∠A=(2x+26)°

and

m ∠B= (3x−29)°

∴ (2x+26)° = (3x−29)°

Now, solve for x

2x + 26 = 3x - 29

26 + 29 = 3x - 2x

55 = x

∴ x = 55

But measure of angle A is given by

m ∠A=(2x+26)°

Put the value of x into the equation,

m ∠A=(2(55)+26)°

m ∠A=(110+26)°

m ∠A = 136°

Hence, the measure of angle (m ∠A) is 136°

Learn more on Vertical angle theorem here: brainly.com/question/24839702

#SPJ1

6 0
2 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
Marcos charges $6 an hour to work in his neighborhoods gardens. Complete the graph to show proportional relationship of the amou
NISA [10]

Answer:

120

Step-by-step explanation:

6 0
3 years ago
Timed test please help. Can someone please help me explain how you graph the circle from the equation below and how you find the
ryzh [129]
Well, you have the radius and the center already. So all you have to do is graph the center point, then count from that center point out 5 units, then draw the circle.
5 0
3 years ago
Read 2 more answers
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