Answer:
![\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}](https://tex.z-dn.net/?f=%5Cboxed%7B-3xy%5E%7B2%7D%5Csqrt%20%5B3%5D%20%7B2x%5E%7B2%7D%7D%7D)
Step-by-step explanation:
Your expression is
![\sqrt [3] {-54x^{5}y^{6}}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B-54x%5E%7B5%7Dy%5E%7B6%7D%7D)
Here's how I would simplify it.
![\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcll%7D%5Csqrt%20%5B3%5D%20%7B-54x%5E%7B5%7Dy%5E%7B6%7D%7D%20%26%20%3D%20%26%20%5Csqrt%20%5B3%5D%20%7B%28-1%29%5E%7B3%7D%5Ctimes%202%20%5Ctimes%2027%20%5Ctimes%20x%5E%7B2%7D%20%5Ctimes%20x%5E%7B3%7D%20%5Ctimes%20y%5E%7B6%7D%7D%20%26%20%5Ctext%7BFactored%20the%20cubes%7D%5C%5C%26%20%3D%20%26%20%5Csqrt%20%5B3%5D%20%7B%28-1%29%5E%7B3%7D%20%5Ctimes%203%5E%7B3%7D%5Ctimes%20x%5E%7B3%7D%20%5Ctimes%20y%5E%7B6%7D%5Ctimes%202%20%5Ctimes%20x%5E%7B2%7D%7D%20%26%20%5Ctext%7BGrouped%20the%20cubes%7D%5C%5C%5Cend%7Barray%7D)
![\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcll%7D%26%20%3D%20%26%20%5Csqrt%20%5B3%5D%20%7B%28-1%29%5E%7B3%7D%20%5Ctimes%20%7B3%5E%7B3%7D%5Ctimes%20x%5E%7B3%7D%20%5Ctimes%20y%5E%7B6%7D%7D%7D%20%5Ctimes%5Csqrt%20%5B3%5D%20%7B%202%20%5Ctimes%20x%5E%7B2%7D%7D%20%26%20%5Ctext%7BSeparated%20the%20cubes%7D%5C%5C%26%3D%26%20%5Cmathbf%7B-3xy%5E%7B2%7D%5Csqrt%20%5B3%5D%20%7B2x%5E%7B2%7D%7D%7D%20%26%20%5Ctext%7BTook%20cube%20roots%7D%5C%5C%5Cend%7Barray%7D)
![\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20simplified%20expression%20is%20%24%5Cboxed%7B%5Cmathbf%7B-3xy%5E%7B2%7D%5Csqrt%20%5B3%5D%20%7B2x%5E%7B2%7D%7D%7D%7D%24%7D)
Answer:
Formula of the area of triangle = 1/2 × b × h (where 'b' is the base and 'h' is the height)
1 hectare = $36
$486 = 13.5 hectares
13.5 hectares = 1/2 × b × h
To get b × h, you use the reverse of the formula. Hence:
13.5 = 1/2 × b × h
13.5 ÷ 1/2 = b × h
= 27
27 is b × h.
The question states that the base is three times the height. Hence:
b = 3u
h = 1u
b × h = 27
= 3u × 1u
Thus, we need to find one value which is three times the other, in order to get a product of 27.
Factors of 27:
1 × 27
3 × 9
9 is three times of 3. Thus, the base is 9, while the height is 3.
Answer:
3.33lbs. repeating?
Step-by-step explanation:
I think it would just be 10/3 and be 3.33333333 and so on. (im just taking a guess)
Step-by-step explanation:
as in the other problem, the table describes mutually exclusive attributes.
so, we can simply sum the numbers up to get the total number of students :
3+9+2+16 = 30 students.
so, when picking a random student, we have 30 possibilities.
now, how many of those 30 have the desired attributes (to have a brother AND a sister) ?
I see 3 in the table.
so, the probability to pick a student that has a brother and a sister is
3/30 = 1/10 = 0.1
To find the x-intercept, substitute 0 for y and solve for x.
-6x + 3(0) = 18.9
-6x = 18.9
x = 18.9 / -6
x = -3.15 <-- Your x-intercept is (-3.15,0)
To find the y-intercept, substitute in 0 for x and solve for y.
-6(0) + 3y = 18.9
3y = 18.9
y = 18.9/3
y = 6.3 (0,6.3) <-- Your x-intercept is (0,6.3)
If this helped, please mark me brainliest, thank you and if you need more help, feel free to message me!