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Bingel [31]
3 years ago
8

What is the equation of this line?

Mathematics
2 answers:
ivann1987 [24]3 years ago
6 0
We know the slope is 2 (because it increases 2 units every one unit) and the y-intercept is 0
y = mx + b
where m is the slope and b is the y intercept

y = 2x

Have an awesome day! :)
Serggg [28]3 years ago
3 0

we know that

The equation of the line in the graph passes through the point (0,0)

so

the linear equation represent a direct variation  

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx

the constant of proportionality k is equal to the slope

We need only one point to determine the equation of the line

Let

A(1,2)

so

(x,y)=(1,2)

Divide the y-coordinate by the x-coordinate to find the slope

m=\frac{y}{x}

m=\frac{2}{1}=2

the equation is

y=2x

therefore

the answer is

<u>the equation of the line is </u>

y=2x

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Step-by-step explanation:

hence the value of y=-9/4and k=-16.

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A box of cereal has the following measurements: length = 16.5 cm; width = 4 cm; height = 30.25 cm. What is the volume of the cer
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Read 2 more answers
Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 10
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Answer:

The function for the outside temperature is represented by T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right], where t is measured in hours.

Step-by-step explanation:

Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:

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Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:

T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]

Where:

\bar T - Mean temperature, measured in degrees.

A - Amplitude, measured in degrees.

\tau - Daily period, measured in hours.

t - Time, measured in hours. (where t = 0 corresponds with 5 AM).

If \bar T = 85\º, A = 15\º and \tau = 24\,h, the resulting function for the outside temperature is:

T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]

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