The answer to the question is the first, third and fifth
<span>y=−3x+2</span> is a linear equation in slope-intercept form with
slope <span>m=<span>(−3)</span></span>
(and y-intercept <span>=2</span>)
We want the equation of a line with slope <span>m=<span>(−3)</span></span> through the point <span>(<span>−2</span>,<span>−8</span>)</span>
Using the point-slope linear equation form:
<span><span>(y−<span>(−8)</span>)</span>=<span>(−3)</span><span>(x−<span>(−2)</span>)</span></span>
Simplifying
<span>y+8=−3x−6</span>
or, in standard form
<span>3x+y=−<span>14</span></span>
Answer:
x+3y=-1
Step-by-step explanation:
y=3x-2 so m=3 old slope
the new slope must be -1/3 (opposite reciprocal of the old slope).
y-y0=m*(x-x0)
y-2=-1/3*(x-(-7))
y-2=-1/3x-1/3*7
y-2=-1/3x-7/3
3y-6=-x-7
The standard form for linear equations in two variables is Ax+By=C.
x+3y=6-7
x+3y=-1
1 kg=1000g*1000mg/1g=1000000mg =10⁶ mg
or you can use proportion
1000g - x mg
1 g -1000mg
x=1000*1000=1000000mg
1kg=10⁶ mg
