Answer:
B) 78
Step-by-step explanation:
The two lines we are going to want to pay attention to for this problem are line S and line Q. ALWAYS remember that a line adds up to 180 degrees. This means that when we find x, we know that 57 + x + another number equals 180, because they are all angles on line S.
So, all we need to do is find this "other number". We can do this by looking at line Q. Again, since all lines add up to 180, the other angle on line Q must be 45 degrees, because 135 and 45 add up to 180. And now we know our "other number", its 45!
But how do we know the "other number" is 45? Well, its because the lines that creat these angles are both parallel (line S and line R) and have the same line crossing them (line Q).
Now we can finish our problem. We should get 57 + x + 45 = 180. This then gives us x = 78.
My answer was wrong sorry
Answer:
9 seconds
Step-by-step explanation:
The complete question is
The altitude of an object, d, can be modeled using the equation below:
d=-16t^2 +vt+h
from the edge of a 486 foot cliff, Peyton shot an arrow over the ocean with an initial upward velocity of 90 feet per second. In how many seconds will the arrow reach the water below?
Let
d ----> the altitude of an object in feet
t ---> the time in seconds
v ---> initial velocity in ft per second
h ---> initial height of an object in feet
we have

we know that
When the arrow reach the water the value of d is equal to zero
we have



substitute the values and solve for t


Multiply by -1 both sides

The formula to solve a quadratic equation of the form
is equal to
in this problem we have
substitute in the formula
the solution is t=9 sec
see the attached figure to better understand the problem
Ok there are 11 animols all together because 1 rabbit + 6 elephants + 2 monkeys + 2 parrots
Answer:
Your answer is D
Step-by-step explanation:
Punching in those equations into my calculator, A, B, and C have all come up as non rational, because
isn't a rational number. It can become rational as soon as you multiply it with another number.