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Stolb23 [73]
3 years ago
15

The ratio of two number is 4:7 and their hcf is 6 .find their lcm​

Mathematics
1 answer:
Alona [7]3 years ago
3 0

168

this is the full process

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Is that 2x squared + 5x? Correct me if I'm wrong.
natulia [17]
Well, what I would do is divide it into two shapes. Cut off the bottom part to make two separate quadrilaterals, and you'd have a square with sides of x. So the area would be x^2. Then, for the remaining piece (rectangle), add the x from the square bit to 5 for one side, and the other side would be x. So you'd have 5x * x, which equals 5x^2. Add the two separate area's together to get the total area, which would give you 6x^2. Hope that helped! :)
4 0
4 years ago
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What is the solution set of{x|X<-3} n {xl x> 5)?
dsp73

Answer:

C) Solution set of{x|X<-3} n {xl x> 5) is an the empty set.

Step-by-step explanation:

Here, the solution set is given as : set of  {x| x < -3 } ∩   {x l x > 5)

Now, defining the each set , we get

{x| x < -3 }   = ( .... -6,-5,-4 ,-3)  = P

and the SET  {x l x > 5} = (5,6,7,........ )  = Q

Now, by taking the intersection of two sets,we get

P ∩ Q = NULL SET as they don not have any element in common.

⇒ {x| x < -3 } ∩   {x l x > 5} is an empty set

Hence, solution set of{x|X<-3} n {xl x> 5) is an the empty set.

6 0
3 years ago
How do you solve this system equation using elimination
laiz [17]
3x +y = 23 this is the same as y=23-3x
3x - 2y = 8 this is the same as 3x/2-8/2=y, which gives you; y=1,5x-4
so;y=23-3xy=1,5x-4
y=y
23-3x=1,5x-4
23+4=1,5x+3x
27=4,5x
27/4,5=x
x=6
the y is:
3*6+y=23
18+y=23
y=23-18
<span>y=5</span>
3 0
4 years ago
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A circle has a diameter of twelve millimeters. What are the circumference and area of the circle? Use three point one four for p
Nady [450]
Its 4.0 because an is in on a seventh
3 0
3 years ago
2(a-3)÷(a-4)(a-5)+a-1÷(3-a)(a-4)+a-2÷(5-a)(a-3) simplify.​
Arlecino [84]

<u><em>I'm almost confident that I did this wrong, but i tried...</em></u>

Answer:

4a-9 ÷ -19

Step-by-step explanation:

(It was easier for me to put it in fractions)

\frac{2(a-3)}{(a-4)(a-5)} + \frac{a-1}{(3-a)(a-4)} + \frac{a-2}{(5-a)(a-3)}        (3-a) (a-4) + (5-a) (a-3)

\frac{2a-6}{(a-4)(a-5)} + \frac{a-1}{(3-a)(a-4)} +  \frac{a-2}{(5-a)(a-3)}      3 - a · a - 4 + 5 - a · a - 3

    \frac{2a-6}{(2a-20)} + \frac{a-1}{(3-a)(a-4)} + \frac{a-2}{(5-a)(a-3)}               3 - a + 1 - a - 3

   \frac{2a-6+a-1+a-2}{(2a-20)+(3-a)(a-4)+(5-a)(a-3)}                        1 - a - a

                 \frac{4a-9}{2a-20+1-2a}                                       1 - 2a

                   \frac{4a-9}{2a-19-2a}

                      \frac{4a-9}{-19}

8 0
3 years ago
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