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2 years ago

How do you do this question? 24 is what percent of 32?

2 answers:

6 0

24 = x% * 32

24= x/100 * 32

Multiply 100 on both sides.

2400 = x * 32

32x = 2400

Divide 32 on both sides.

x = 2400/32

x = 75

75 percent of 32 is 24

DedPeter [7]2 years ago

3 0

75%
You do 24/32=x/100 and solve for x to find percentage of something. 24/32=.75 then multiply .75 by 100 and you get the answer 75%.

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You are wrapping a gift box that is 16 inches long, 7 inches wide, and 9 inches tall. Find the amount of wrapping paper you need

Svetach [21]

Answer:

638 in.²

Step-by-step explanation:

Assuming you need to cover just the surface area of the box with no overlaps, and the shape is a rectangular prism, then you need to find the surface area of a rectangular prism.

SA = PH + 2LW

where

P = perimeter of base = 2(L + W),

H = height of prism

L = length of base

W = width of base

SA = 2(16 + 7)(9) + 2(16)(7)

SA = 638

5 0

2 years ago

matrenka [14]

Answer:

a) -8

b) 9

c) -7

Simplify

a) -1

b) 5

c) 3

d) -32

e) 27

8 0

2 years ago

What is the MAD of the data set? {10, 9, 16, 5, 10}

Oksanka [162]

First, you'd find the mean of all the numbers by doing 10+9+16+5+10 = 50/5 = 10. Second, you'd subtract all values from the mean by doing
16 - 10 = 6
10 - 10 = 0
10 - 10 = 0
10 - 9 = 1
10 - 5 = 5
Lastly, finding the mean of all 5 numbers would be, 2.4! Hope this helps!! :D

5 0

2 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

2 years ago

What is the distance between 23 and -8 on a number line?

elena55 [62]

Answer: 31

Step-by-step explanation:

To find the distance, find the difference between the number.

23 - (-8) = 31 So the distance is 31 units.

Note: To go from -8 to 23 you will have to add 31 to -8 and to go from 23 to -8 you will have to subtract 31 so the distance is 31

7 0

3 years ago