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NikAS [45]
3 years ago
9

Simplify completely 14x^5y^4 +21x^3y^2/ 7x^3y

Mathematics
2 answers:
Studentka2010 [4]3 years ago
6 0

Answer:

C.2x^{2}y^{3}+3y

Step-by-step explanation:

We have the expression:

\frac{14x^5y^4+21x^3y^2}{7x^3y}

which can be separeded in two terms, like this:

\frac{14x^5y^4}{7x^3y} +\frac{21x^3y^2}{7x^3y}

and now we can simplify each term, dividing the coefficients and using the exponent law \frac{x^m}{x^n} =x^{m-n} (when we divide a variable we substract the exponts) and we get the following:

2x^{5-3}y^{4-1}+3x^{3-3}y^{2-1}

simplifying the exponents:

2x^{2}y^{3}+3y

which is option C.

ss7ja [257]3 years ago
3 0

C is the answer you have to divide 21 by 3 first which gives you 3. The x cubed cancels out because when dividing exponents you have to subtracting. The y squared minus y gives you just y. This explains the 3y

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