Question

Simplify completely 14x^5y^4 +21x^3y^2/ 7x^3y

Answer 1

Answer:

C.$2x^{2}y^{3}+3y$

Step-by-step explanation:

We have the expression:

$\frac{14x^5y^4+21x^3y^2}{7x^3y}$

which can be separeded in two terms, like this:

$\frac{14x^5y^4}{7x^3y} +\frac{21x^3y^2}{7x^3y}$

and now we can simplify each term, dividing the coefficients and using the exponent law $\frac{x^m}{x^n} =x^{m-n}$ (when we divide a variable we substract the exponts) and we get the following:

$2x^{5-3}y^{4-1}+3x^{3-3}y^{2-1}$

simplifying the exponents:

$2x^{2}y^{3}+3y$

which is option C.

Answer 2

C is the answer you have to divide 21 by 3 first which gives you 3. The x cubed cancels out because when dividing exponents you have to subtracting. The y squared minus y gives you just y. This explains the 3y