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2 years ago

In a week 13 hens laid 78 eggs what is the unit rate for eggs per hen?

Mathematics

1 answer:

uranmaximum [27]2 years ago

6 0

Answer:

6 eggs per hen

Step-by-step explanation:

78/13=6 eggs per hen

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There were 10 students in a teacher's classroom. The next week, there were 19 students. What is the percent increase

mixas84 [53]

Answer:

Step-by-step explanation:

7 0

2 years ago

Phones-R-Us charges $16.95 per month and $0.05 per text message. Awesome Wireless charges $22.95 per

Dima020 [189]

Answer:

$S \leq 200$

Step-by-step explanation:

Given

Phone R-Us= $16.95 + $0.05 per SMS

Awesome Wireless = $22.95 + $0.02 per SMS

Required

Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us

Represent the SMS with S

For Phone R-Us, we have:

$SMS = 16.95 + 0.05S$

For Awesome Wireless, we have:

$SMS = 22.95 + 0.02S$

For Awesome Wireless is greater or equal to Phone R-Us, we have:

$22.95 + 0.02S \geq 16.95 + 0.05S$

Collect Like Terms

$0.02S - 0.05S \geq 16.95 - 22.95$

$-0.03S \geq -6$

Solve for S

$\frac{-0.03S}{-0.03} \geq \frac{-6}{-0.03}$

$S \leq 200$

<em>Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200</em>

4 0

2 years ago

A chemist is using 333 milliliters of a solution of acid and water. If 19.6% of the solution is acid, how many milliliters of ac

sesenic [268]

65.27mm of acid is present in solution.

Step-by-step explanation:

Given,

Quantity of solution = 333mm

Acid Percentage = 19.6%

Quantity of acid = 19.6% of Quantity of Solution

$Quantity\ of\ acid=\frac{19.6}{100}*333\\Quantity\ of\ acid=\frac{6526.8}{100}\\Quantity\ of\ acid=65.27mm$

65.27mm of acid is present in solution.

Keywords: Percentage

Learn more about percentages at:

#LearnwithBrainly

3 0

2 years ago

3. For the graph, complete the following: (a) Write a table of ordered pairs from the graph. (b) Write an equation from the tabl

alexandr1967 [171]

for this i am working on this um please wait

6 0

2 years ago

I need help with this ASAP plzzzzz

miss Akunina [59]

Answer:

23. $\frac{4\sqrt{3} }{3}$

24. $\frac{7\sqrt{3}}{3}$

25. $6\sqrt{3}$

26. $\frac{10\sqrt{3} }{3}$

27. $14$

28. $4\sqrt{3}$

Step-by-step explanation:

To solve these i used SOHCAHTOA

$sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}$

23.

Find the missing side using Tangent

$tan(30)=\frac{x}{4}$

$4*tan(30)=x$

$\frac{4\sqrt{3} }{3}$

24.

Find the missing side using Tangent

$tan(30)=\frac{x}{7}$

$7*tan(30)=x$

$\frac{7\sqrt{3}}{3}$

25.

Find the missing side using Tangent

$tan(30)=\frac{x}{18}$

$18*tan(30)=x$

$6\sqrt{3}$

26.

Find the missing side using Tangent

$tan(30)=\frac{x}{10}$

$10*tan(30)=x$

$\frac{10\sqrt{3} }{3}$

27.

Find the missing side using Tangent

$tan(30)=\frac{x}{14\sqrt{3} }$

$(14\sqrt{3}) *tan(30)=x$

$14$

28.

Find the missing side using Tangent

$tan(30)=\frac{x}{12}$

$12*tan(30)=x$

$4\sqrt{3}$

5 0

3 years ago