All categories

3 years ago

Use the figure to find the segment length or angle measure.

Mathematics

1 answer:

Likurg_2 [28]3 years ago

3 0

A...................

You might be interested in

Factorise each of the following.

kupik [55]

Step-by-step explanation:

a) 2(32-4j+8k-jk)

b)a(3a-ab+3c -bc)

c)m(2m - mn + 2n - n^2)

5 0

3 years ago

Write and solve the equation that represents the sentence below.

Afina-wow [57]

Answer:

The equation should be 18x = 109.8

The answer is 6.1.

It can be solved using the division property of equality.

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Please help, it's urgent!

Aneli [31]

For this case we have to, by defining properties of powers and roots the following is fulfilled:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

We must rewrite the following expression:

$\sqrt [3] {8 ^ {\frac {1} {4} x}}$

Applying the property listed we have:

$\sqrt [3] {8 ^ {\frac {1} {4} x}} = 8 ^ {\frac{\frac {1} {4} x} {3} }= 8 ^ {\frac {1} {4 * 3} x} = 8 ^ {\frac {1} {12} x}$

Using the property again we have to:

$8 ^ {\frac {1} {12} x} = \sqrt [12] {8 ^ x}$

Thus, the correct option is option C

Answer:

Option C

6 0

4 years ago

Read 2 more answers

Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i

dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

$v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s$

Also,

$v=r\omega$

Where

$\omega$ is the angular speed

So,

$\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s$

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

8 0

3 years ago

Find the length of MN

serg [7]

Answer:

Is there supposed to be a screenshot?

then again this is your first question .....................

6 0

3 years ago