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3 years ago

PLEASE HELP EASY 6TH GRADE MATH! WHOEVER DOES THE BEST GETS BRAINLIEST PLZZZZZZ?

Mathematics

1 answer:

zhuklara [117]3 years ago

8 0

Answer:

1.B 2.B 3.A

Step-by-step explanation:

1.(70-24)/2 = 23

2. 295 x 8.95 =2640.25 - 400 = 2240.25 ~ $2000

3. 21hoursx48 weeks x 2years = 2016 hours ~ 2000

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Karl is making a pot of chili. The recipe calls for StartFraction 3 Over 8 EndFraction cup of chili powder, but Karl only wants

muminat

Answer:

3/16 or 3 over 16

Step-by-step explanation:

Find half of 3/8:

1/2x3/8 = 3/16

3 0

3 years ago

Ax+by=(a-b) , bx - ay =(a+b) simultaneous linear equations using cross multiplication

Molodets [167]

Answer:

$x=1\,,\,y=-1$

Step-by-step explanation:

Given: $ax+by=a-b\,,\,bx-ay=a+b$

To solve: the given linear equations

Solution:

Consider the equations:

$A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0$

By method of cross multiplication:

$\frac{x}{B_1C_2-B_2C_1}=\frac{y}{C_1A_2-C_2A_1}=\frac{1}{A_1B_2-A_2B_1}$

For equations: $ax+by=a-b\,,\,bx-ay=a+b$

$ax+by-(a-b)=0\\bx-ay-(a+b)=0$

Take $A_1=a\,,\,B_1=b\,,\,C_1=-(a-b)\,,\,A_2=b\,,\,B_2=-a\,,\,C_2=-(a+b)$

So,

$\frac{x}{-b(a+b)-a(a-b)}=\frac{y}{-b(a-b)+a(a+b)}=\frac{1}{-a^2-b^2}\\\frac{x}{-ab-b^2-a^2+ab}=\frac{y}{-ab+b^2+a^2+ab}=\frac{1}{-(a^2+b^2)}\\\frac{x}{-(a^2+b^2)}=\frac{y}{a^2+b^2}=\frac{1}{-(a^2+b^2)}\\\frac{x}{-(a^2+b^2)}=\frac{1}{-(a^2+b^2)}\,,\,\frac{y}{a^2+b^2}=\frac{1}{-(a^2+b^2)}\\x=1\,,\,y=-1$

6 0

3 years ago

Please answer immediately.

salantis [7]

1. Angle L

2. A

3. Side PL

4. Side AR

5. A and K

6. B

7. Side Br

8. A

9. T

10. TA

4 0

2 years ago

Can someone help me with system of equations?

nignag [31]

2x + y = 350
x + 2y = 475
3x + 3y = 825
x + y = 275
x = 275 - y
(plug back into first equation)
2(275 - y) + y = 350
550 - 2y + y = 350
550 - y = 350
-y =-200 or y = $200 (dog)
therefore, x = $75 (cats)
Check
2(75) + 200 = 350
75 + 400 = 475
HAPPINESS! :)

3 0

2 years ago

Choose the correct description of the graph of the compound inequality x − 3 < −9 or x + 5 greater than or equal to 10.

forsale [732]

X - 3 < 9 or x + 5 ≥ 10
+ 3 + 3 - 5 - 5
x < 12 or x ≥ 5

Solution Set: {x|x < 12 or x ≥ 5}, (-∞, 12) or (5, ∞)

8 0

3 years ago

Read 2 more answers