Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
• 1 + cot² x = csc²x and csc x = 
• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Consider the left side
sin²Θ( 1 + cot²Θ )
= sin²Θ × csc²Θ
= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified
-----------------------------------------------------------------
Consider the left side
cos²Θ - sin²Θ
= cos²Θ - (1 - cos²Θ)
= cos²Θ - 1 + cos²Θ
= 2cos²Θ - 1 = right side ⇒ verified
Answer:
21
Step-by-step explanation:
Given the following expressions
f(x) = x³-2x
g(x) =-x-2
We are to find (fog)(-5)
fog = f(g(x))
f(g(x)) = f(-x-2)
Replace x with -x-2 in f(x)
f(-x-2) = (-x-2)³-2(-x-2)
f(-x-2) = (-x-2)³+2x+4
fog = (-x-2)³+2x+4
Substitute x = -5 into the result
fog(-5) = (-x-2)³+2x+4
fog(-5) = (-(-5)-2)³+2(-5)+4
fog(-5) = (5-2)³-10+4
fog(-5) = 3³-6
fog(-5) = 27-6
fog(-5) = 21
Hence the required result of the composite function is 21
Answer:
Im not sure but i think its A=1, B=0, and C=9
Step-by-step explanation:
hope this helps
If you mean you get them by diving them by 100 or something over 100(as in a fraction) that's the answer, I'm incredibly sorry if it is not what you meant!
