In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
Answer:
1/625
Explanation:
In case of multiplication of numbers with same base, we add the powers.
This means that:
a^x * a^y = a^(x+y)
Applying this to the given, we will find that:
(5^-1) * (5^-3) = 5^(-1-3)
= 5^-4
= 1/625
Hope this helps :)
Answer:
X <u>></u> 7
Step-by-step explanation:
X <u>></u> 7
Answer:
( 3x -2)
Step-by-step explanation:
6x^2 – 7x + 2
We know that the constant only has factors of 1 and 2
Since the middle term is negative we know that that we are subtracting
A negative times a negative is positive for the final term
A negative plus a negative is negative for the middle term
( -1 ) ( -2)
We have to determine how to break up 6x^2
1x * 6x
2x*3x
3x*2x
6x*1x
We are given that one factor is 2x-1
( 2x -1 ) ( -2)
That means the other factor of 6x^2 is 3x ( 2x*3x)
( 2x -1 ) ( 3x -2)
you want things less than or equal to 5
so A and B
