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slavikrds [6]
3 years ago
10

FiftyFifty adult men in the United States are randomly selected and measured for their body mass index​ (BMI). Based on that​ sa

mple, it is estimated that the average​ (mean) BMI for men is 26.526.5​, with a margin of error of 3.23.2. Use the given statistic and margin of error to identify the range of values​ (confidence interval) likely to contain the true value of the population parameter.
Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
6 0

Answer:

(23.3, 29.7)

Step-by-step explanation:

We are given the following information  the question:

Sample mean = 26.5

Sample size = 50

Margin of error = 3.2

Confidence Interval:

\text{Sample mean} \pm \text{Margin of error}\\= 26.5 \pm 3.2 = (23.3, 29.7)

Thus, the true value of the population parameter lies in the range (23.3, 29.7)

Fynjy0 [20]3 years ago
3 0

Answer: (23.3,\ 29.7)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\overline{x}\pm ME., where \overline{x} is the sample mean and ME is the margin of error .

Given : The sample mean : \overline{x}=26.5

Margin of error : ME=3.2

Then , the range of values​ (confidence interval) likely to contain the true value of the population parameter will be :-

26.5\pm 3.2=(26.5-3.2,\ 26.5+3.2)=(23.3,\ 29.7)

Hence, the range of values​ likely to contain the true value of the population parameter =  (23.3,\ 29.7)

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Hey, There i hope you are haveing a great day :) So I look at the example so it should be the same I think like how you work out the mean by adding all the numbers and then diving them so,  (8 + 4 + 8 + 8 + 10 + 2 + 4 + 4) = 48 and now you know you have got 8 numbers there a divide them so 48/8 = 6. and then I think you take away it so, 8 - 6 = 2 4 - 6 =-2 8 - 6 = 2 8 - 6 = 2 10 - 6 = 4 2 - 6 = -4 4 - 6 = -2 4 - 6 = -2 and then 2 + -2 + 2 + 2 + 4 + -4 + -2 + -2 divide 8 = 0 and you can't divide anything by 0 so that would be the answer.  

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