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3 years ago

6

Panera serves broccoli cheddar soup every 5 days & chicken noodle soup every 3 days. If both were served today, how many day

s will it be before they are both served again

1 answer:

GarryVolchara [31]3 years ago

4 0

Answer: The answer would be 15.

Step-by-step explanation: The is because 15 is the Least Common multiple of each number. Ex. 3,6,9,12,(15) 5,10,(15)

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The results of a survey show that the percent of adults in a certain town who want to change the name of the town is in the inte

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A) the middle of the range is 39.5% b) the difference between the middle and the ends of the range is ±1.5% c) less than a majority favor change. Change seems unlikely.

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3 years ago

What does rename mean

schepotkina [342]

<span>It means to give a new name to someone or something.</span>

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3 years ago

John went to the grocery store and purchased cans of soup and frozen dinners. Each can of soup has 150 mg of sodium and each fro

Fantom [35]

Answer:

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Step-by-step explanation:

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3 years ago

1.5 lbs of gum balls I want to buy it’s 3.99 per pound

zubka84 [21]

Answer:

$5.99 for 1.5 lbs of gumballs

Step-by-step explanation:

You want to buy One and a half pounds of gumballs for $3.99 per pound. It is 3.99 for one pound of gumballs, so the price for half a pound of gumballs is half of that price.

3.99 / 2 = 1.995

Then add the price of 1 pound

3.99 + 1.995 = 5.985

Then you can round that up to 5.99

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3 years ago

Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis

wariber [46]

Answer:

a) $P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368$

b) $P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}, x>0$

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

$X \sim Exp(\lambda=\frac{1}{30000})$

The cumulative distribution function is given by:

$F(X) = 1- e^{-\frac{x}{\mu}}$

Part a

We want to find this probability:

$P(X>30000)$ and for this case we can use the cumulative distribution function to find it like this:

$P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368$

Part b

For this case w want to find this probability

$P(X>30000|X>15000)$

We have an important property on the exponential distribution called "Memoryless" property and says this:

$P(X>a+t| X>t)=P(X>a)$

On this case if we use this property we have this: $P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)$

We can use the definition of the density function and find this probability:

$P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607$

7 0

3 years ago