Answer:
it will take 3 yrs for the value of camera to reach $162.
Step-by-step explanation:
<u>Pd</u><u> </u><u>=</u><u> </u><u>P</u><u>(</u><u>1</u><u>-</u><u>R</u><u>/</u><u>1</u><u>0</u><u>0</u><u>)</u><u>^</u><u>T</u>
<u>1</u><u>6</u><u>2</u><u> </u><u>=</u><u> </u><u>3</u><u>8</u><u>4</u><u>(</u><u>1</u><u>-</u><u>2</u><u>5</u><u>/</u><u>1</u><u>0</u><u>0</u><u>)</u><u>^</u><u>T</u>
<u>1</u><u>6</u><u>2</u><u>/</u><u>3</u><u>8</u><u>4</u><u> </u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>
<u>2</u><u>7</u><u>/</u><u>6</u><u>4</u><u> </u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>
<u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>3</u><u> </u><u>=</u><u> </u><u> </u><u>(</u><u>3</u><u>/</u><u>4</u><u>)</u><u>^</u><u>T</u>
<u>T</u><u> </u><u>=</u><u> </u><u>3</u>
Let 'c' represent the number of pictures Chelsea took.
Let 's' represent the number of pictures Sonya took.
For last year's Thanksgiving, c + s = 236
For this year's Thanksgiving, let 'x' represent the number of photos taken in total. x = c + s, where c and s are two integers that are the same (c = s).
And we know that for both years, c + s + x = 500.
As we know that c + s is already 236 from last year, we can remove c + s from the equation in bold and replace it with 236 instead.
236 + x = 500.
Now we have to isolate the x term.
x = 500 - 236
x = 264.
We know that x = c + s, where c and s are the same, so we can just use one of the variables and double it (so you either get 2c or 2s - it doesn't matter which one you pick because they're both the same).
2c = 264
c = 132
c = s
s = 132.
Both took 132 pictures this year.
A negative minus a negative is always a positive ;)
Answer:
C
Step-by-step explanation:
I was again led to this question, Brainly seems to enjoy doing this, and i might as well say something. Glad you figured it out and i hope you get it right.
