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scZoUnD [109]
3 years ago
7

Suppose you buy a 1.25-pound package of ham at $5.20 per pound. (a) What fraction of a pound did you buy? (b) How much money did

you spend?
Mathematics
2 answers:
FrozenT [24]3 years ago
5 0
25/100=1/4
a) you bought 1 1/4 pound of ham
b) $6.50
1.25 x $5.20=$6.50
victus00 [196]3 years ago
3 0

Answer:

(a) \frac{5}{4}

(b) $ 6.5

Step-by-step explanation:

Given,

The number of pounds of ham bought = 1.25,

(a) Thus, the fraction of a pound bought = \frac{\text{number of pounds bought}}{\text{1 pound}}

=\frac{1.25}{1}

=\frac{125}{100}

=\frac{5}{4}

(b) We have,

The cost of ham of 1 pound = $ 5.20,

So, the amount spend on ham = the fraction of a pound bought × price per pound

= \frac{5}{4}\times 5.20

= 5 × 1.3

= $ 6.5

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3 years ago
For a walk-a-thon a sponsor committed to give you a flat free of $5 plus $2 for every mile m you walk
Iteru [2.4K]

Answer:

$45

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION BELOW;

For a walk-a-thon a sponsor committed to give you a flat fee of $5 plus $2 for every mile you walk. If you walk for 20 miles, what is the total amount you will collect from your sponsor at the end of the walk-a-thon?

$5 was given for participants of the walk-a-thon.

$2 was given for every miles won

Then, for "y" number of miles, the the amount that can be won is ( 2×y)= 2y

The Total amount that can be given

= (5 + 2y)

Where "y" is the miles value

Then, if you walk for 20 miles, The Total amount that can be given

= 5 + 2(20)

= 5+ 40

= $45

3 0
2 years ago
In ​ kite PQRS ​, TQ=5 cm and TR=12 cm. What is SR ? <br><br> Enter your answer in the box.
ozzi
The square of the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two sides.
You can use Pythagoras' Theorem to calculate QR:
a^2 + b^2 = c^2
5^2 + 12^2 = QR^2
25 + 144 = QR^2
169 = QR^2
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3 0
3 years ago
For the following pair of functions, find (f+g)(x) and (f-g)(x).
ch4aika [34]

Given:

The functions are

f(x)=4x^2+7x-5

g(x)=-9x^2+4x-13

To find:

The functions (f+g)(x) and (f-g)(x).

Solution:

We know that,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x^2+7x-5-9x^2+4x-13

(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)

(f+g)(x)=-5x^2+11x-18

And,

(f-g)(x)=f(x)-g(x)

(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)

(f+g)(x)=4x^2+7x-5+9x^2-4x+13

(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)

(f-g)(x)=13x^2+3x+8

Therefore, the required functions are (f+g)(x)=-5x^2+11x-18

and (f-g)(x)=13x^2+3x+8.

7 0
3 years ago
If x is a positive integer, then x is _____ negative.
faltersainse [42]
A. never

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