Answer:
C
Step-by-step explanation:
To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
The answer is 4 because you round down due to the .2 not being greater than 5
Answer:
No
Step-by-step explanation:
Put x = 2 into both equations:
For x- 10 = 2-10 = 8 (Not > 8)
For -0.5x-4 = -0.5*2-4 = -5 (Not < -8)
Hence, the answer is no.
Answer:
x₁ = 0
x₂ = 6
Step-by-step explanation:
9x² - 54x = 0
9x(x - 6) = 0
x(x - 6) = 0
x = 0
x - 6 = 0 → x = 6
Hope this helps! :)
