Answer:
ill talk
Step-by-step explanation:
Distances in 2- and 3-dimensions (and even higher dimensions) can be found using the Pythagorean theorem. The straight-line distance can be considered to be the hypotenuse of a right triangle whose sides are the horizontal and vertical differences between the coordinates.
Here, you have A = (0, 0) and B = (3, 6). The horizontal distance between the points is ...
... 3 - 0 = 3 . . . . the difference of x-coordinates
The vertical distance between the points is ...
... 6 - 0 = 6 . . . . the difference of y-coordinates
Then the straight-line distance (d) between the points is found from the Pythagorean theorem, which tells you ...
... d² = 3² + 6²
... d = √(9 + 36) = √45 ≈ 6.7 . . . units
Answer:
Surface area of cylinder = 50.26 unit² (Approx.)
Step-by-step explanation:
Given:
Radius of base r = 2 units
Width of lateral rectangle = 4 units
Length of lateral rectangle = 6.28 units
Find:
Surface area of cylinder
Computation:
Surface area of cylinder = 2[Area of base] + Area of lateral rectangle
Surface area of cylinder = 2[πr²] + [l][b]
Surface area of cylinder = 2[(22/7)(2)²] + [6.28][4]
Surface area of cylinder = 2[(22/7)(4)] + 25.12
Surface area of cylinder = 25.14 + 25.12
Surface area of cylinder = 50.26
Surface area of cylinder = 50.26 unit² (Approx.)
I hope this helps you
?.12%=72
?.12=72.100
?=6.100
?=600