Answer:
4750
Step-by-step explanation:
475000/100 = 4750
4750 * 6 = 28500
4750 * 5 = 23750
28500 - 23750 = 4750
we have
we know that
<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms
p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.
So
in this problem
the constant term is equal to 
and the first monomial is equal to 
-----> coefficient is 
So
possible values of p are 
possible values of q are 
therefore
<u>the answer is</u>
The all potential rational roots of f(x) are
(+/-)
,(+/-)
,(+/-)
,(+/-)
,(+/-)
,(+/-)
On March 8, 2017, one U.S. dollar was worth 19.61 Mexican pesos, 149.23 pesos was worth 7.61 dollars and 63.64 dollars was worth 1247.98 pesos
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
One U.S. dollar = 19.61 Mexican pesos
a) 149.23 pesos = 149.23 pesos * One U.S. dollar per 19.61 Mexican pesos = 7.61 dollars
b) 63.64 dollars = 63.64 dollars * 19.61 Mexican pesos per dollar = 1247.98 pesos
On March 8, 2017, one U.S. dollar was worth 19.61 Mexican pesos, 149.23 pesos was worth 7.61 dollars and 63.64 dollars was worth 1247.98 pesos
Find out more on equation at: brainly.com/question/2972832
#SPJ1
Answer: x=2
Step-by-step explanation:
2(5x+3)=26
Distribute the 2
10x+6=26
Subtract 6 from both sides
10x=20
Divide both sides by 10
x=2
<h3>
Answer: False</h3>
==============================================
Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
--------------------------
Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
