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timurjin [86]
3 years ago
14

Write a function called cipher(phrase,shift)that accepts two parameters: a string phrase and an integer shift.The integer shift

can be positive, negative or zero.

Computers and Technology
1 answer:
Aleks [24]3 years ago
7 0

Answer:

Following is given the code according to requirement.

The code is attached as an image so that the indentation is understood by the user. Comments are given inside the code where necessary.

The output of code is also attached as well  in end.

I hope it will help you!

Explanation:

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6. Consider a circle of diameter d cm.
blagie [28]

Circles

Area of Circle is \pi d^{2} /4

Total percentage increase in the area of the modified circle is 69%

Explanation:

(a)  Given the diameter of the circle be d

Then the radius of the circle = r = d/2

and the area of the circle is given by:

 

Area(A) = \pi r^{2}  

A = \pi (d/2)^{2}

A = \pi d^{2} /4

The area of circle is \pi d^{2} /4

(b)

The increase in percentage while changing the dimensions is given by the formula  :

Total % increase = a% + b% - (a% * b%)/100

Where ,

a% is the percentage increase in side a

b% is the percentage increase  in side b

Let the percentage increase in radius is : a%

Since a% = b%

So the formula is

Total increase % = a% + a% + (a% * a%)/100

Given here the diameter of the circle increases by 30% so a =30

Therefore, putting the value of a in the formula

Total increase % = 30% + 30% + (30% *30%)/100

Total increase % = 60% + 9%

Total increase % =69%

Therefore the total percentage increase in the area of the modified circle is 69%

8 0
3 years ago
Write an algorithm to print the minimum and maximum of an integer array. Your need to pass the array as a parameter. Since we ca
sammy [17]

Answer:

See explaination

Explanation:

MinMax.java

import java.util.*;

public class MinMax

{

static void MinMax(int[] arr)

{

int Min=arr[0]; // initializinf min and max with 1st value of array

int Max=arr[0];

for(int i=0;i<arr.length;i++) // iterating loop only once

{

if(arr[i]>Max) // checking max value

{

Max=arr[i];

}

if(arr[i]<Min) // checking min value

{

Min=arr[i];

}

}

System.out.println("Min Number is "+Min); //printing min value

System.out.println("Max Number is "+Max); //printing max value

}

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

System.out.print("Enter N value: "); // taking n value

int n=sc.nextInt();

int[] arr=new int[n];

System.out.println("Enter N elements:"); // taking n elements into array

for(int i=0;i<n;i++)

{

arr[i]=sc.nextInt(); // each element into the array

}

MinMax(arr); // calling MinMax() method.

}

}

4 0
3 years ago
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