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il63 [147K]
2 years ago
10

You respond to a fire at a pharmaceutical production plant. One of the outside storage tanks is on fire. The placard on the tank

shows the ID number is 1053. What is this material?
Computers and Technology
1 answer:
monitta2 years ago
6 0

Answer:

Hydrogen sulfide.

Explanation:

Hydrogen sulfide is a chemical compound formed due to the reaction of hydrogen and sulfur. It is a colorless, corrosive, poisonous and highly flammable gas having the foul smell of rotten eggs.

Under the United Nations/North America number datasheet, the identification number for hydrogen sulfide is 1053.

In this scenario, you respond to a fire at a pharmaceutical production plant. One of the outside storage tanks is on fire. The placard on the tank shows the ID number is 1053. Therefore, this material is hydrogen sulfide.

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The correct answer would be either (b) or (d).

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The correct answer would be (b).

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If you have columns that are truncating your content (not showing all the content), but you cannot increase the width of the wor
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Answer:

Use the Wrap text button

Explanation:

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3 years ago
Which of the following is considered both an input and output peripheral?
larisa [96]
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3 years ago
As we have seen in this chapter, public-key cryptography can be used for encryption and key exchange. Furthermore, it has some p
Savatey [412]

Answer:

Disadvantages of public key cryptography is that : Assymetric cryptography is slower than the private key cryptography.

Explanation:

We are dealing with big data applications most of time. Almost all applications are data intensive. Private key cryptography which is also known as symmetric cryptography. Symmetric cryptography based systems are faster. Since there is no key transmitted with the data, encrypted data can be transferred over the channel or session even if the path is vulnerable or have chances of interception as the chances of decrypting the data is almost impossible.

Also, The identity of the receiver is guaranteed using the password based authentication used by symmetric crypto systems. Only the trusted receiver who has the access to the secret key can only decrypt the payload

Public Key Cryptography is slower than private key cryptography. Today’s application’s are data intensive. In case of data intensive applications , encrypting huge data will take a lot more time than that of symmetric key cryptography. Whenever Bulk data transmission is needed symmetric key cryptography is preferred. Secret key based crypto systems have proven to be more faster than any currently available assymetric key based crypto systems.

7 0
2 years ago
Write a Java application with a main() to find the two largest distinct integers entered on the command line by the user. We are
Setler [38]

Answer:

import java.util.Scanner; // Scanner class is to use input output functions

public class TwoDistinctLargest //class to find two distinct largest nos

{

public static void main(String[] args) { //start of main() function

Scanner input = new Scanner(System.in); // creates Scanner type object

       int integers = 0, largest1 = 0, largest2 = 0; // declare variables

/* integers holds the input integer values, largest1 has 1st largest number and largest 2 contains second distinct largest number, i is used as the count variable to move through the input integers */

       int i = 0;  

//prompts user to enter integers and enter 0 to stop

       System.out.println("Enter the integers (press 0 to stop): ");

       integers = input.nextInt(); //reads and scans input integers

       while(integers != 0) {

/* the loop keeps taking integer values from user until the value of integers is equal to 0, this means until the user enters 0 */

//checks if the value of integer is greater than first largest computed number

           if(integers > largest1) {

//if the value in largest1 is greater than that of largest2

               if(largest1 > largest2) {

                   largest2 = largest1; } // then value of largest1 is set to largest2                

               largest1 = integers; // largest1 now holds the value of integers //which means largest1 holds the first distinct largest integer

           } else { //checks if the value of integers is greater than largest2

               if(integers > largest2) {

//if the value of integers is not equal to that of largest1

                   if(integers!=largest1)  {

// set the value of second distinct largest number to largest2

                   largest2 = integers;}              }            }

                     i++; //keeps moving to the next input integer

           integers = input.nextInt();     //keeps taking input integers    }      

//prints the two distinct largest integers

       System.out.println("\n The 1st largest distinct integer is " + largest1);

       System.out.println("\n The 2nd largest distinct integer is " + largest2); } }

Explanation:

Lets suppose the user inputs the following integers

1, 6, 5, 6, 0

Initial values are:

integers = 0

largest1 = 0

largest2 = 0

i = 0

When the user enters 1, then value of integers = 1

while loop checks if integers!=0. As integers =1 so the program enters the body of while loop. The first IF condition is checked if(integers > largest1)

As largest1 = 0 and integers =1 so this condition evaluates to true as 1 > 0

So the statements in the body of this IF condition are executed. This if conditions contains another if statement if(largest1 > largest2) which checks if the value largest1 is greater than that of largest2. Its false because largest1 =0 and largest2 =0 so largest1 = largest2, so the statement of this if condition body will not execute and program moves to this                 largest1 = integers; statement which sets the value of integers i.e. 1 to largest1. So the value of largest1 = 1

Now the i is incremented by 1 and it points at second value of integers= 6.

while loop checks if integers!=0. As integers =6 so the program enters the body of while loop. The first IF condition is checked if(integers > largest1)

As largest1 = 1 and integers =6 so this condition evaluates to true as 6>1

So the statements in the body of this IF condition are executed. This if conditions contains another if statement if(largest1 > largest2) which checks if the value largest1 is greater than that of largest2.

Its true because largest1 =1 and largest2 =0 so largest1 > largest2, so the next statement is executed largest2 = largest1; So now the value of largest2=1.

Now program moves to this largest1 = integers; statement which sets the value of integers i.e. 6 to largest1. So the value of largest1 = 6

Now the i is incremented by 1 and it points at second value of integers= 5.

while loop condition is again true. IF condition is checked if(integers > largest1)

As largest1 = 6 and integers =5 so this condition evaluates to false as 5<6. So this IF part will not execute and program control moves to the else part.

Else part has an if condition if(integers > largest2) which evaluates to true because integers = 5 and largest2 = 1 so the program moves to next if statement inside the previous if statement of else part i.e. if(integers!=largest1). This if statement is the main statement which will help in finding two distinct largest numbers in case the same largest value is input more than once. It checks If the value of integers is not equal to largest1 value. As integers = 5 and  largest1 = 6 so this if condition is true. If this condition is not used in this program then largest2 will not be assigned distinct largest values but assigned 6 for both largest1 and largest2 as 6 is input twice. Next this if statement  largest2 = integers assigns value of integers to largest2 which is the second largest distinct integer.

Now the i is incremented by 1 integers value become 0.

while loop checks if integers!=0. As integers =0 so the while loop breaks. The last two print statements which produce following output.

The 1st largest distinct integer is: 6

The 2nd largest distinct integer is: 5

7 0
3 years ago
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