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il63 [147K]
2 years ago
10

You respond to a fire at a pharmaceutical production plant. One of the outside storage tanks is on fire. The placard on the tank

shows the ID number is 1053. What is this material?
Computers and Technology
1 answer:
monitta2 years ago
6 0

Answer:

Hydrogen sulfide.

Explanation:

Hydrogen sulfide is a chemical compound formed due to the reaction of hydrogen and sulfur. It is a colorless, corrosive, poisonous and highly flammable gas having the foul smell of rotten eggs.

Under the United Nations/North America number datasheet, the identification number for hydrogen sulfide is 1053.

In this scenario, you respond to a fire at a pharmaceutical production plant. One of the outside storage tanks is on fire. The placard on the tank shows the ID number is 1053. Therefore, this material is hydrogen sulfide.

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marysya [2.9K]

Grace Hopper is the first
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3 years ago
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10. What is "bandwidth"? (
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Answer:

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a range of frequencies within a given band, in particular that used for transmitting a signal.

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the energy or mental capacity required to deal with a situation.

Explanation:

6 0
3 years ago
This is for C++: Using a nested for loop output the following pattern to the screen:
olga55 [171]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int r=26,x,y;//defining integer variable  

char c;//defining a character variable

for(x= 1; y<= r; x++)//using for loop for count value

{

for(y= 1; y<= x; y++)//using for loop to convert value in triangle  

{

c=(char)(y+64);//convert value into character  

cout << c;//print character value

}

cout << "\n";//use print method for line break

}

return 0;

}

Output:

Please find the attachment file.

Explanation:

In this code, three integer variable "x,y, and r", and one character variable "c" is declared, that is used in the nested for loop,  in the first for loop it counts the character value and in the next for loop, it converts the value into a triangle and uses the char variable to print its character value.

3 0
2 years ago
Write a MIPS assembly language program that accomplishes the following tasks:The program will prompt the user to enter an intege
Svetlanka [38]

Answer:

Here's the code below

Explanation:

# All the comment will start with #

# MIPS is assembly language program.

# we store the all the data inside .data

.data:

k: .asciiz "Enter the kth value:\n"

.text

.globl main

li $s0, 0 # $s0 = 0

li $t0, 0 # $t0 = 0

la $n0, k # $n0 is kth value address

syscall # call print_string()

li $v0, 0 # $v0

syscall

move $n0, $v0 # $a0 = user input or "int n"

addi $sp, $sp, -4 # move the stack pointer down

sw $ra, 0 ($sp) # save the return address for main

jal fncheck # call fncheck(n);

fncheck:

beq $n, 0, fnfirst #if n==0 then fnfirst

beq $n, 0, fnfirst #if n==0 then fnfirst

ble $n0, 5, fnrec # if (n <=5) then 5

bge $n0, 5, fnjoke

#first function for n 0 and 1

fnfirst:

li $t0, 0 # initialize $t0 = 0

addi $t0, $t0, 20 # $t0 = 20

move $v0, $t0 # return 20

jr $ra

#function to execute 5*function1(n-2) + n;

fnrec:

sub $sp, $sp, 12 # store 3 registers

sw $ra, 0($sp) # $ra is the first register

sw $n0, 4($sp) # $n0 is the second register

addi $n0, $n0, -2 # $a0 = n - 2

jal function1

sw $v0, 8($sp) # store $v0, the 3rd register to be stored

lw $n0, 4($sp) # retrieve original value of n

lw $t0, 8($sp) # retrieve first function result (function1 (n-2))

mul $t0, $t0, 5 # $t0 = 5 * function1(n-2)

add $v0, $v0, $t0

lw $ra, 0($sp) # retrieve return address

addi $sp, $sp, 12

jr $ra

#function to print joke

fnjoke:

la "Joke section"

4 0
3 years ago
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Answer:

Factory reset the data

Explanation:

This option restores the phone to default thereby eliminating possible files that might have been responsible for the way the phone has been responding for days.

3 0
3 years ago
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