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scoray [572]
3 years ago
9

Find the least common multiple of 4 and 7

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
4 0

<em><u>Answer: The least common multiple of 4 and 7 is 28.</u></em>


Step-by-step explanation:

↓↓↓↓↓↓↓↓

First, find the prime factorization of 4.

2×2=4

Next, find the prime factorization of 7.

7×1=7

Then, multiply each factor the greater number of times it occurs.

7×2×2=28

Hope this helps!

Thank you for posting your question.

-Charlie

olga nikolaevna [1]3 years ago
3 0

28 is the least common multiple. To find the least common multiple, you look through the numbers both 4 and 7 go into. The smallest of those number is the least common multiple, or LCD.

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3 years ago
A postal employee can sort 3 batches
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Step-by-step explanation:

Use proportions

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Zolol [24]

Answer:

y = 8

Step-by-step explanation:

Two triangles are said to be congruent if all the three sides and three angles of both triangles are equal.

The distance between two points on the coordinate plane is given as:

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In triangle ABC:

|AB|=\sqrt{(2-8)^2+(6-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|AC|=\sqrt{(5-8)^2+(0-4)^2}=5\\\\|BC|=\sqrt{(5-2)^2+(0-6)^2    }=\sqrt{45}

In triangle MNO:

|MN|=\sqrt{(1-7)^2+(2-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|MO|=\sqrt{(4-7)^2+(y-4)^2}\\\\|NO|=\sqrt{(4-1)^2+(y-2)^2    }

Since triangle ABC and triangle MNO are congruent, hence:

|AB| = |MN| = 2√10, |AC| = |MO| = 5, |BC| = |NO| = √45

|AC|=|MO|=5\\\\\sqrt{(4-7)^2+(y-4)^2}=5\\\\(4-7)^2+(y-4)^2=25\\\\9 +(y-4)^2=25\\\\(y-4)^2=16\\\\square\ root\ of\ both\ sides:\\\\y-4=4\\\\y=4+4\\\\y=8

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3 years ago
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Answer:

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