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Doss [256]
2 years ago
11

Some one plz help!!! due in 10 min

Mathematics
1 answer:
Rzqust [24]2 years ago
3 0

Step-by-step explanation:

since f'(x) = 2f(x) and f(3) has no term of x (so, there must be a constant that eliminates x for x = 3), we get

f(x) = x²/9 × c

c = m×e^n

f(1) = 1/9 × m×e^n = 5

=> m×e^n = 45

f(3) = 9/9 × m×e^n = 45

m = 45

n = 0

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one bus leaves a stop every 9 minutes a second bus leaves every 15 minutes if they both leave at 1:25 at what time will they nex
aleksandrvk [35]
<span>In this question you need to find the lowest common multiple. I like to do it the factor tree way:<span>
<span>      15             9</span>
    /   \           / \
   3    5        3   3
See how there are both a 3 in the 15 factor tree and there is at least on three in the 9 factor tree. So when you find the LCM, you combine the two threes from the different factor trees like this:
3 x 5 x 3 = 45
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Now simply add the 45mins onto the 1:25 

<span>Answer: 2:10  </span></span></span>
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