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2 years ago

Some one plz help!!! due in 10 min

Mathematics

1 answer:

Rzqust [24]2 years ago

3 0

Step-by-step explanation:

since f'(x) = 2f(x) and f(3) has no term of x (so, there must be a constant that eliminates x for x = 3), we get

f(x) = x²/9 × c

c = m×e^n

f(1) = 1/9 × m×e^n = 5

=> m×e^n = 45

f(3) = 9/9 × m×e^n = 45

m = 45

n = 0

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Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot represents class first. From the first box plot, we get

$\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89$

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