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Nimfa-mama [501]
3 years ago
15

What is the formula for Inflation Rate?

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0
Inflation Rate= CPI2-CPI1/CP1 x 100

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The length of ZX is 2 units.<br><br><br>What is the perimeter of triangle XYZ?
Alika [10]

Answer:

5+3 square root of 5 units

7 0
2 years ago
A number is chosen at random from 1 to 25. Find the probability of selecting an odd number or multiples of 5. *
Ymorist [56]

Answer:

Odd number: 13/25 (52%)

Multiples of 5: 5/25 (20%)

Step-by-step explanation:

There are 13 odd numbers between 1 and 25 so you have a 13/25 chance which is 52% (13/25 = 0.52). There are 5 multiples of 2 between 1 and 25 so you have a 5/25 chance which is 20% (5/25 = 0.2).

8 0
3 years ago
PLEASE HELP I WILL GIVE YOU BRAINLIEST!!
LiRa [457]

Answer: 48 feet squared is the answer

Step-by-step explanation: All you do is take the length which is 8 and multiply it by the width which is 6, and the answer is 48.

I hope it helped comment if you have questions. :)

4 0
3 years ago
(23/5) divided (-33/4)
Romashka [77]

Step-by-step explanation:

(23/5)÷(-33/4)

multiply the first by the second reverse

23/5×4/-33

multiply the numerator between them and the denomination between them

92/-165

-0.558

5 0
3 years ago
While researching the cost of school lunches per week across the state, you use a sample size of 45 weekly lunch prices. The sta
Drupady [299]

We assume the lunch prices we observe are drawn from a normal distribution with true mean \mu and standard deviation 0.68 in dollars.


We average n=45 samples to get \bar{x}.


The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write


\sigma = 0.68 / \sqrt{45} = 0.101


Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains \mu.


Our interval takes the form of ( \bar{x} - z \sigma, \bar{x} + z \sigma ) as \bar{x} is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".


Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.


Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.


With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.


We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is


( \bar{x} - 1.65 (.101),  \bar{x} + 1.65 (.101) )


in other words a margin of error of


\pm 1.65(.101) = \pm 0.167 dollars


That's around plus or minus 17 cents.




3 0
3 years ago
Read 2 more answers
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