I'll do the first one to get you started
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The equation x^2 + x - 6 = 0 is the same as 1x^2 + 1x + (-6) = 0. It is in the form ax^2 + bx + c = 0
We see that a = 1, b = 1, c = -6. Those values will be plugged into the quadratic formula (see attached image for steps).
The answers are x = -3 and x = 2. The order of the roots does not matter.
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To factor 1x^2 + 1x - 6, we need to find two numbers such that they add to 1 (the x coefficient) and multiply to -6 (the constant term)
Two such numbers are 3 and -2. This is found through trial and error.
Note how 3 plus -2 = 1 and 3 times -2 = -6.
So x^2 + x - 6 = 0 becomes (x+3)(x-2) = 0. You can use the FOIL rule to get x^2+x-6 back again.
Now use the zero product property to solve
(x+3)(x-2) = 0
x+3 = 0 or x-2 = 0
x = -3 or x = 2
which are the two solutions we got when we used the quadratic formula.
It evolved from the intermingling of various Indian traditions and beliefs.
If two unrelated triangles, then C mainly because you're not given any information on DEF.
If ABC=DEF, then the answer would be A.
Answer:
y = -2x-18
y = 3/2x + 11/4
Step-by-step explanation:
Answer:
I will answer in a general way because the options are not given.
We know that the area of model A is smaller than the area of model B.
For model A, we have 72 shaded sections, out of 100.
Then the quotient of model A is:
72/100 = 0.72
For model B we have 10 sections, and x shaded ones.
Because model B is greater than model A, we know that:
x/10 should be larger than 72/100
then we have the inequality:
x/10 > 0.72
x > 0.72*10
x > 7.2
And we can not have more than 10 shaded sections (because there is a total of 10 sections) then:
10 ≥ x > 7.2
Then x can be any whole number in that interval.
the possible values of x are:
x = 8
x = 9
x = 10