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2 years ago

Y=3 csc x how do i solve this

1 answer:

4 0

The period of the function can be calculated using 2π|b|2⁢π|b|.Period: 2π|b|2⁢π|b|Replace bb with 11 in the formula for period.Period: 2π|1|

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For geometry:( i’ll give a brainist!!!

kvasek [131]

<h3>Answer: Angle Q = 133 degrees</h3>

========================================================

Work Shown:

Recall that for any triangle, the three angles always add to 180

P+Q+R = 180

(x+13) + (10x+13) + (2x-2) = 180

(x+10x+2x) + (13+13-2) = 180

13x+24 = 180

13x = 180-24

13x = 156

x = 156/13

x = 12

Now that we know x, we can find the angle measures

angle P = x+13 = 12+13 = 25 degrees
angle Q = 10x+13 = 10*12+13 = 120+13 = 133 degrees
angle R = 2x-2 = 2*12-2 = 24-2 = 22 degrees

As a way to check if we have the right answer or not, we see that,

P+Q+R = 25+133+22 = 180

So the answer is confirmed.

4 0

2 years ago

O número 2021 tem resto 5 quando dividido pelo nmr 6, 7, 8, e pelo nmr 9. Quantos múmeros inteiros positivos menores do que 2021

Leokris [45]

336

Step-by-step explanation:

2021-5=2016÷6=336

8 0

2 years ago

3/6x4/9 plz help meeeeee

Aleonysh [2.5K]

Answer:

12/54

Step-by-step explanation:

4x3=12

6x9=54

3 0

3 years ago

Read 2 more answers

Please help me with this...

mr_godi [17]

I dont see anything u have to post on here whats the question you need help on ?

5 0

3 years ago

Read 2 more answers

Find the equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5).

neonofarm [45]

The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is $y = \frac{-1}{3}x - 8$

Solution:

Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)

We have to find the equation of line

The slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Let us first find the slope of line

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that product of slopes of given line and slope of line perpendicular to given line is equal to -1

Slope of given line $\times$ slope of line perpendicular to given line = -1

$3 \times \text{ slope of line perpendicular to given line }= -1$

$\text{ slope of line perpendicular to given line } = \frac{-1}{3}$

Let us now find the equation of line with slope $m = \frac{-1}{3}$ and containing the point (-9, -5)

Substitute $m = \frac{-1}{3}$ and (x, y) = (-9, -5) in eqn 1

$-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8$

Thus the required equation of line is:

Substitute $m = \frac{-1}{3}$ and c = -8 in eqn 1

$y = \frac{-1}{3}x - 8$

Thus the required equation of line perpendicular to given line is found

6 0

3 years ago