Question

Two true-breeding stocks of pea plants are crossed. One parent has red, axial flowers and the other has white, terminal flowers; all F1 individuals have red, axial flowers. The genes for flower color and location assort independently. Among the F2 offspring, what is the probability of plants with white axial flowers? A) 9/16 B) 1/16 C) 3/16 D) 1/4

Answer 1

Answer:

Answer is 3/16.

Explanation:

If the F1 progeny has red axial flowers this shows us that red and axial genes are dominant. If we say that R is for red dominant gene, r is for white recessive gene.

If we say A is axial dominant gene, a is for terminal recessive gene.

All F1 progeny has AaRr phenotype.

When we cross them, Aa x Aa  can have AA Aa Aa aa

When Rr x Rr crossed, RR Rr Rr rr

The F2 progeny can have white axial flowers by having a and R in the phenotype with the possibility having aa= 1/4 , R in the phenotype , the possibility is 3/4.

1/4 x 3/4 = 3/16 in all F2 progeny