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Digiron [165]
3 years ago
6

PLEASE HELP ME WITH FUNCTIONS I REALLY NEED IT

Mathematics
1 answer:
garik1379 [7]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Range is on the y-axis & Domain sits on the x-axis

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Which of the sets shown includes the elements of set Z that are both odd numbers and multiples of 7? Z = {−21, −14, −7, 0, 7, 14
valentinak56 [21]

Answer:

11

Step-by-step explanation:

f 7? Z = {−21, −14, −7, 0, 7, 14, 21}

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3 years ago
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(7th grade work) How many gallons of water were in the bucket after 1 second? Explain your thinking.
Hunter-Best [27]

Answer:

one-third of a gallon is in the bucket

Step-by-step explanation:

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3 years ago
What is 11.25 as a fraction?
s2008m [1.1K]
11.25 is 11 1/4 because if you were to do 1 divided by 4, you would find that the answer is 0.25. But if you need an improper fraction, you would get 45/4 because if you were to put 11 times 4, you would get 44, and 44+1=45. Then you put that on the numerator spot, and you will get 45/4 for improper fraction.
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4 years ago
The product of the first three terms of a geometric progression is 3375, and their sum is 65. Find the first term of this progre
artcher [175]

Answer:

  5 or 45

Step-by-step explanation:

If the first term is "a" and the common ratio is "r", then the first three terms are ...

  a, ar, ar²

Their product will be ...

  a × ar × ar² = (ar)³ = 3375

  ar = ∛3375 = 15

Their sum will be ...

  a + ar + ar² = 65 = 15/r + 15 + 15r

Subtracting 15 and multiplying by r/5, we have the quadratic in r:

  10r = 3 + 3r²

  3r² -10r +3 = 0 . . . . in standard form

  (3r -1)(r -3) = 0 . . . . factored

  r = 1/3 . . or . . 3 . . . . values of r that make the factors zero

The first term is 15/r = 45 or 5

_____

The first three terms could be 5, 15, 45; or they could be 45, 15, 5.

5 0
3 years ago
A coach jogs 1.8 miles on Monday, 1.3 miles on Tuesday, and 1.2 miles on Wednesday. If the coach's friend jogs twice as far as t
Bond [772]

Answer:

Coach's friend jog <u>8.6 miles</u>.

Step-by-step explanation:

Given:

A coach jogs 1.8 miles on Monday, 1.3 miles on Tuesday, and 1.2 miles on Wednesday.

If the coach's friend jogs twice as far as the coach.

Now, to find the miles the coach's friend jog.

<em>Coach jogs on Monday = 1.8 miles.</em>

<em>Coach jogs on Tuesday = 1.3 miles.</em>

<em>Coach jogs on Wednesday = 1.2 miles.</em>

Total miles coach jog <em>= </em>1.8+1.3+1.2=4.3\ miles.<em />

As, coach's friend jogs twice as coach.

So, to get the miles coach's friend jogs multiply total miles coach jog by 2 we get:

Total\ miles\ coach\ jog\times 2

 4.3\times 2\\\\=8.6\ miles.

Therefore, coach's friend jog 8.6 miles.

4 0
3 years ago
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