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Ilia_Sergeevich [38]
3 years ago
6

Average atomic masses listed by IUPAC are based on a study of experimental results. Bromine has two isotopes 73 br and81 br, who

se masses (78.9183 and 80.9163 amu) and abundances (50.69% and 49.31%) were determined in earlier experiments. Calculate the average atomic mass of bromine based on these experiments.
Chemistry
1 answer:
ddd [48]3 years ago
5 0

<u>Answer:</u> The average atomic mass of element bromine is 80.4104 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i .....(1)

  • <u>For _{35}^{79}\textrm{Br}[/tex] isotope:</u>

Mass of _{35}^{79}\textrm{Br} isotope = 78.9183 amu

Percentage abundance of _{35}^{79}\textrm{Br} isotope = 50.69 %

Fractional abundance of _{35}^{79}\textrm{Br} isotope = 0.5069

  • <u>For _{35}^{81}\textrm{Br} isotope:</u>

Mass of _{35}^{81}\textrm{Br} isotope = 80.9163 amu

Percentage abundance of _{35}^{81}\textrm{Br} isotope = 49.31 %

Fractional abundance of _{35}^{81}\textrm{Br} isotope = 0.4931

Putting values in equation 1, we get:

\text{Average atomic mass of Bromine}=[(78.9183\times 0.5069)+(80.9163\times 0.4931)]

\text{Average atomic mass of Bromine}=80.4104amu

Hence, the average atomic mass of element bromine is 80.4104 amu.

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Assuming that the final (equilibrium) temperature of the system is above the melting point of ice, such that all ice in the container melts in this process thus

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The temperature of the system therefore remains at 0 \; \textdegree{\text{C}}; the only macroscopic change in this process is expected to be observed as a slight variation in the ratio between the mass of liquid water and that of the ice in this system.

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