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Gre4nikov [31]
4 years ago
8

A water balloon is tossed into the air with an upward velocity of 25 ft/s. Its height h(t) in ft after t seconds is given by the

function h(t) = − 16t2 + 25t + 3. Show your work.
19. After how many seconds will the balloon hit the ground? ​(hint: Use the quadratic formula)
Mathematics
1 answer:
Anna [14]4 years ago
5 0
Given 
h(t)=-16t^2+25t+3
assume h(t) is height measured upwards from ground.
Need h(t)=0 for t>0.
solve
<span>h(t)=-16t^2+25t+3=0
</span>use quadratic formula, A=-16, B=25, C=3
t=(-B +/- sqrt(B^2-4AC))/2A
=-25-sqrt(25^2+192)/(-32)
= {-0.11198, 1.6745} seconds
reject negative root, so
time = 1.6745 seconds.
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