Question

During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser beams at the moon's surface to determine its distance from Earth. The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon? Based on the relationship Distance = Speed times Time, solve the problem.

Answer 1

Answer:

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

$v = \frac{d}{t}$

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that $t = 2.52$.

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that $v = 3*10^{8}$m/s.

We have to find d. So:

$v = \frac{d}{t}$

$d = vt$

$d = 3*10^{8}*2.52$

$7.56*10^{8]$

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.