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mylen [45]
4 years ago
6

During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be

ams at the moon's surface to determine its distance from Earth. The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon? Based on the relationship Distance = Speed times Time, solve the problem.
Mathematics
1 answer:
rusak2 [61]4 years ago
7 0

Answer:

The distance between the astronomers and the moon was 7.56*10^{8] meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

v = \frac{d}{t}

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that t = 2.52.

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that v = 3*10^{8}m/s.

We have to find d. So:

v = \frac{d}{t}

d = vt

d = 3*10^{8}*2.52

7.56*10^{8]

The distance between the astronomers and the moon was 7.56*10^{8] meters.

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