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Serjik [45]
3 years ago
5

there are 18 bikes in a rack. there are 4 more blue bikes than yellow, and 2 less yellow bikes than green bikes. how many bikes

of each color are in the rack?
Mathematics
1 answer:
Dmitry [639]3 years ago
7 0
6 yellow 2 blue 8 green
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SoIve the system of equations by elimination. (Addition)<br> 1)-2x + 4y = -22<br> 2x + 8y = –26
Rufina [12.5K]

Answee:

We have these two equations:

-2x +4y =-22

2x + 8y -26

We need to try to get the same number multiplying both x or y, I think we can make the 2 of the first equation negative, for that, we multiply all the equation by -1:

2x + 8y =-26  ---- -2x - 8y =26

Now we have this:

-2x +4y = -22

-2x -8y = 26

Now e substract both equations:

-2x - (-2x) +4y -(-8y) = -22-26

12y = -48

Y = -48/12 = -4

And we replace to get x

-2x + 4y = -22

-2x +4*(-4)=-22

-2x - 16 = -22

x= -6/-2 =3

6 0
3 years ago
Read 2 more answers
What is the probability that a junior non-Nutrition major and then a sophomore Nutrition major are chosen at random? Express you
aleksandr82 [10.1K]

Answer:

0.0032

The complete question as seen in other website:

There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.

Step-by-step explanation:

Total number of in a nutrition class = 111 students

To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.

Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)

Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)

There are 13 number of junior non-Nutrition major

Pr (j non-N) = 13/111

Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)

Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)

There are 3 number of sophomore Nutrition major

Pr (S N-major) = 3/111

The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111

= 39/12321

= 0.0032

7 0
4 years ago
What the answer fast
Dominik [7]

To solve this problem, first let x=0.933333(repeating). Then, you want to multiply both sides by 10 to get 10x = 9.33333 (repeating). Next, take equation 2 and minus equation 1 from it giving you 9x = 8.4. Finally, multiply both sides by 10 and you will get 90x = 84. Divide both sides by 90 giving x=84/90. Answer is 84/90. 84/90 can reduce to 14/15.

3 0
3 years ago
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