Answer:
b) no solution
Step-by-step explanation:
What you always want to do in this type of problem is to combine all of your "like terms," where like terms are the part of your equation that have the same variable (or no variable). In this equation, we see three terms that have the variable "z". We can add the 12z + 15z on the left side to get 27z, and then we subtract 27z on both sides to cancel both of the 27z terms out.
Now, we are left with -6 = -5 (because we got rid of all the terms with the variable z in them). We know that -6 does not equal -5, and therefore, there is no number that we can assign to variable z such that the left side of the equation will equal the right side of the equation.
Therefore, there is no solution (because a solution to the equation would be a value that we can plug into the variable z to make the equation true).
Answer: 35%
Step-by-step explanation:
8 + 5 + 7 = 20
50% = 10
25% = 5
10% = 2
5% = 1
25% + 10% = 5+2
35% = 7
Answer:
and
do not lie on the line
Step-by-step explanation:
Given

Required
Determine which points that are not on the line
First, we need to determine the slope (m) of the line:

Where


So;



Next, we determine the line equation using:

Where


becomes


To determine which point is on the line, we simply plug in the values of x to in the equation check.
For 
and 
Substitute 4 for x and 2 for y in 



<em>This point is on the graph</em>
<em></em>
For 
and
Substitute 4 for x and 3 for y in 



<em>This point is not on the graph</em>
<em></em>
For 
and 
Substitute 7 for x and 2 for y in 



<em></em>
<em>This point is not on the graph</em>
<em></em>
<em></em>
<em></em>
<em></em>
and<em> </em>
<em></em>
<em>Substitute </em>
<em> for x and </em>
<em> for y in </em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em>This point is on the graph</em>
Answer:
A and C are proportional relationships.
Step-by-step explanation:
Recall that a "proportional relationship" has no constant term. Thus, we eliminate Answers B and D immediately.
Answer A represents a proportional relationship: y varies directly with the square of x.
Answer C also represents a proportional relationship: y varies directly with x.
3+c i think that the answer.