I can’t do it rn so just dm me later
Answer:
perimeter goes with the one that has 5x^2
i dont know the second im sorry
Step-by-step explanation:
Answer:
(3, 0) and (5, 0)
Step-by-step explanation:
we have
![y=x^{2}-8x+15](https://tex.z-dn.net/?f=y%3Dx%5E%7B2%7D-8x%2B15)
we know that
The x-intercepts are the values of x when the value of y is equal to zero
so
For y=0
![x^{2}-8x+15=0](https://tex.z-dn.net/?f=x%5E%7B2%7D-8x%2B15%3D0)
The formula to solve a quadratic equation of the form
is equal to
![x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
in this problem we have
so
![a=1\\b=-8\\c=15](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D-8%5C%5Cc%3D15)
substitute in the formula
![x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-8%29%5Cpm%5Csqrt%7B-8%5E%7B2%7D-4%281%29%2815%29%7D%7D%20%7B2%281%29%7D)
![x=\frac{8\pm\sqrt{4}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B8%5Cpm%5Csqrt%7B4%7D%7D%20%7B2%7D)
![x=\frac{8\pm2} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B8%5Cpm2%7D%20%7B2%7D)
![x=\frac{8+2} {2}=5](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B8%2B2%7D%20%7B2%7D%3D5)
![x=\frac{8-2} {2}=3](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B8-2%7D%20%7B2%7D%3D3)
so
x=3, x=5
therefore
The x-intercepts are (3,0) and (5,0)
Answer:
THE ANSWER IS 4 I SWEAR
Step-by-step explanation: