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Nimfa-mama [501]
3 years ago
8

I need help with number 13, 14, 15 and 16 please

Mathematics
1 answer:
katovenus [111]3 years ago
8 0

The picture is sideways can you flip it?

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y=\sqrt[3]{-x}-3\ and\ x\in(-8;\ 8)\\\\subtitute\ x=-8\ and\ x=8\ to\ the\ equation:\\\\y=\sqrt[3]{-(-8)}-3=\sqrt[3]8-3=2-3=-1\\\\y=\sqrt[3]{-8}-3=-2-3=-5\\\\Answer:\boxed{\{y|-5 \ \textless \  y \ \textless \  -1\}}\to\fbox{b.}
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The average THC content of marijuana sold on the street is 10.5%. Suppose the THC content is normally distributed with standard
MA_775_DIABLO [31]

a. This information is given to you.

b. We want to find

\mathrm{Pr}\{X > 8.9\}

so we first transform X to the standard normal random variable Z with mean 0 and s.d. 1 using

X = \mu + \sigma Z

where \mu,\sigma are the mean/s.d. of X. Now,

\mathrm{Pr}\left\{\dfrac{X - 10.5}2 > \dfrac{8.9 - 10.5}2\right\} = \mathrm{Pr}\{Z > -0.8\} \\\\~~~~~~~~= 1 - \mathrm{Pr}\{Z\le-0.8\} \\\\ ~~~~~~~~ = 1 - \Phi(-0.8) \approx \boxed{0.7881}

where \Phi(z) is the CDF for Z.

c. The 76th percentile is the value of X=x_{76} such that

\mathrm{Pr}\{X \le x_{76}\} = 0.76

Transform X to Z and apply the inverse CDF of Z.

\mathrm{Pr}\left\{Z \le \dfrac{x_{76} - 10.5}2\right\} = 0.76

\dfrac{x_{76} - 10.5}2 = \Phi^{-1}(0.76)

\dfrac{x_{76} - 10.5}2 \approx 0.7063

x_{76} - 10.5 \approx 1.4126

x_{76} \approx \boxed{11.9126}

5 0
1 year ago
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