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kaheart [24]
3 years ago
12

I need help please?!!!!

Mathematics
2 answers:
vladimir2022 [97]3 years ago
6 0

Answer: The answer would be .03 or A.

Step-by-step explanation: You add all of the marbles up to get a total of 10 then you divide 10 by 3 and you get 3.333333333 but then you just take off the 3 before the decimal. DONT USE THIS ON ANY OTHER EQUATIONS!!! This only happens to work with this equation!!!

hoa [83]3 years ago
3 0
Yea I’m gonna with the is 0.3 and A too
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If a is an arbitrary nonzero constant, what happens to a/b as b approaches 0
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On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.

The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.

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Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The
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Answer:

C. H0 : p = 0.8 H 1 : p ≠ 0.8

The test is:_____.

c. two-tailed

The test statistic is:______p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

The p-value is:_____. 0.09887

Based on this we:_____.

B. Reject the null hypothesis.

Step-by-step explanation:

We formulate null and alternative hypotheses as  proportion of people who own cats is significantly different than 80%.

H0 : p = 0.8 H 1 : p ≠ 0.8

The alternative hypothesis H1 is that the 80% of the  proportion is different and null hypothesis is , it is same.

For a two tailed test for significance level = 0.2 we have critical value  ± 1.28.

We have alpha equal to 0.2  for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28

The test statistic is

p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

Where p = 0.8 , q = 1-p= 1-0.8= 0.2

n= 200

Putting the values

0.8 ± 1.28 \sqrt{\frac{0.8*0.2}{200} }

0.8 ± 0.03620

0.8362, 0.7638

As the calculated value of z lies within the critical region  we reject the null hypothesis.

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