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geniusboy [140]
3 years ago
12

Write the equation of the line that passes through the point (2, 4) and has a slope of 3

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

Step-by-step explanation:

y - 4 = 3(x - 2)

y - 4 = 3x - 6

y = 3x - 2

standard form

-3x + y = -2

lidiya [134]3 years ago
3 0

Answer:

this will be step by step so bear with me

Step-by-step explanation:

first you must plug it into the point slope form

y-y1=m(x-x1)

plug in

y-y1=3(x-2)

distribute the three into the ()

y-4=3x-6

now add 4 to both sides

y=3x-2

now standard form

Ax+By=C

y=3x-2

add 2 to both sides

y+2=3x

subtract y from both sides

2=3x-y

flip around the equation

3x-y=2

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Are AB and CD parallel, perpendicular, or neither?*<br> 1. A(-4, 8), B(4, 10), C(1, 1), D(-2, 13)
ohaa [14]

Answer:

Perpendicular

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Step-by-step explanation:

Given

A = (-4, 8)

B = (4, 10)

C = (1, 1)

D = (-2, 13)

Required

Is AB and CD parallel?

First, we need to calculate the slope (m) of AB and CD

m = \frac{y_2 - y_1}{x_2 - x_1}

For AB:

A (x_1,y_1)= (-4, 8)

B(x_2,y_2) = (4, 10)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

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For CD:

C(x_1,y_1) = (1, 1)

D(x_2,y_2) = (-2, 13)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{13 - 1}{-2 - 1}

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For Lines to be parallel, the slope must be equal:

i.e. m_1 = m_2

This condition is not true because:

\frac{1}{4} \neq -4

For Lines to be perpendicular, the slope must be:

m_1 = -\frac{1}{m_2}

This implies:

\frac{1}{4} = -\frac{1}{-4}

\frac{1}{4} = \frac{-1}{-4}

\frac{1}{4} = \frac{1}{4}

<em>Hence, the lines are perpendicular</em>

6 0
3 years ago
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