Question

What is the domain function y=^4sqrtx-1

Answer 1

Answer:

Domain of y=$\sqrt[4]{x-1}$: is x>=1

Interval notation: [1,∞)

Step-by-step explanation:

We have y=$\sqrt[4]{x-1}$

1) The domain of a function is the set of x values for which the function is real and defined.

2) So, x-1 should be positive means x-1>=0, because fourth root of any negative value would be a complex number and not a real number.

3) Now we solve the inequality x-1>=0

4) Adding 1 to both sides of the inequality we get,

x-1+1 > = 0+1

5) Cancel out -1 and +1 from the left side

6) We get x>=1

It concludes that for the domain of the given function, the x value must be greater than or equal to 1